Simplify the expression: sinA + \(cosA\over tan(90-A)\)
2sinA
The correct answer is Option 1 i.e. 2sinA.
sinA + \(cosA\over tan(90-A)\)
tan(90 - A) = cotA
⇒ sinA + \(cosA\over cotA\)
⇒ sinA + \(cosA\over {cosA\over sinA}\)
⇒ sinA + sinA = 2sinA
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