$2\cosec A$
The task is to simplify the following trigonometric expression:
\( \frac{\sin A}{1-\cos A} + \frac{1-\cos A}{\sin A} \)
Identify the common denominator for the two fractions, which is \((1-cos A)sin A\).
Rewrite the expression with the common denominator:
\( \frac{\sin^2 A}{(1-\cos A)\sin A} + \frac{(1-\cos A)^2}{\sin A (1-\cos A)} \)Combine the numerators over the common denominator:
\( \frac{\sin^2 A + (1-\cos A)^2}{(1-\cos A)\sin A} \)Expand the squared term in the numerator: $(1-cos A)2 = 1 - 2cos A + cos2 A$.
\( \frac{\sin^2 A + 1 - 2\cos A + \cos^2 A}{(1-\cos A)\sin A} \)Use the Pythagorean identity $sin2 A + cos2 A = 1$.
Substitute \(1\) for $sin2 A + cos2 A$:
\( \frac{1 + (1 - 2\cos A)}{(1-\cos A)\sin A} \)Simplify the numerator:
\( \frac{2 - 2\cos A}{(1-\cos A)\sin A} \)Factor out \(2\) from the numerator:
\( \frac{2(1 - \cos A)}{(1-\cos A)\sin A} \)Cancel the common factor \((1 - cos A)\), assuming \( A \neq 2n\pi \):
\( \frac{2}{\sin A} \)Apply the reciprocal identity \(cosec A = 1/sin A\):
\( 2\cosec A \)The simplified expression is \(2\cosec A\).
Simplify: (1 - sec2θ)(1 - sinθ)(1 + sinθ)(1 + cot2θ)
From a point on the ground, the angles of elevation of the top and the bottom of a flag that is mounted on an 18 m high pole are respectively 60° and 30°. The height of the flag is:
If θ is an acute angle, find the denominator D when,
(cotθ - cosecθ)2 = \((1 - cosθ)\over D\)
Simplify the expression: sinA + \(cosA\over tan(90-A)\)
\(cos45° \over{tan30°+ cot60°}\) is equal to:
If sec4A = cosec(3A - 50°), where 4A and 3A are acute angles, find the value of cosec(A + 25°).
If cos4θ - sin4θ = k, then the value of \({1-k}\over{1+k}\) is:
Which of the following options gives the correct expression for y when \({cos^2A}\over{1-sinA}\) = y, and sinA ≠ 1?
If \(\sin \theta = \frac{3}{5}\), find \(\cos \theta\).
(secθ + tanθ)/(secθ - tanθ) is equal to:
If tan 45°, cot θ then the value of θ, in radians is
ABC is a triangle If sin (A+B)/2 = √3/2, then the value of sin C/2 is
The angles of elevation of the top of a temple, from the foot and the top of a building 30 m high, are 60° and 30° respectively. Then height of the temple is
what is the principal value of \(\sin^{-1} \left( \sin \dfrac{2 \pi}{3} \right)\) ?