Simplify: \(9^2 + \sqrt{4^2} - 7\sqrt{16} - 7\).
50
Evaluate each term separately using the order of operations.
\(9^2 = 81\).
\(\sqrt{4^2} = \sqrt{16} = 4\).
\(7\sqrt{16} = 7 \times 4 = 28\).
Now substitute back: \(81 + 4 - 28 - 7\).
\(81 + 4 = 85\), then \(85 - 28 = 57\), then \(57 - 7 = 50\).
Hence, the simplified value of the expression is 50.
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Simplify the given expression using BODMAS.
$\frac{4}{11} \times \frac{121}{16} \times 24 (75^2 - 55^2) \times \frac{1}{100}$
Important Questions from Bodmas Rule
The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:
The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:
The value of 20 ÷ 5 of 8 × [9 ÷ 6 × (6 - 3)] - (10 ÷ 2 of 20) is:
The value of \(\left( {18 \div 2\;of\frac{1}{4}} \right)\; \times \;\left( {\frac{2}{3} \div \frac{3}{4}\; \times \;\frac{5}{8}} \right) \div \left( {\frac{2}{3} \div \frac{3}{4}of\frac{3}{4}} \right)\) is:
The value of 18 ÷ [26 - {25 - (15 - 5) ÷ 2}] of 12 + 2 - 2 ÷ 4 × 16 is:
