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Question

Simplify: \(\left(\frac{340}{17}\right) \times \left(\frac{156}{13}\right) + \left(\frac{1484}{28}\right) - \left(\frac{14}{10}\right)\)

This question was previously asked in
RRB NTPC 2025 Under Graduate CBT 1 Question Paper PDF (20-Jun-2026) (Shift 3)
The correct answer is

291.6

Simplify each term: \(\frac{340}{17} = 20\) and \(\frac{156}{13} = 12\), so the product is \(20 \times 12 = 240\).

Next, \(\frac{1484}{28} = 53\) and \(\frac{14}{10} = 1.4\).

Combine following BODMAS: \(240 + 53 - 1.4 = 291.6\).

Hence, the simplified value is 291.6.

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Important Questions from Bodmas Rule

  1. The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:

  2. The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:

  3. The value of 20 ÷ 5 of 8 × [9 ÷ 6 × (6 - 3)] - (10 ÷ 2 of 20) is:

  4. The value of \(\left( {18 \div 2\;of\frac{1}{4}} \right)\; \times \;\left( {\frac{2}{3} \div \frac{3}{4}\; \times \;\frac{5}{8}} \right) \div \left( {\frac{2}{3} \div \frac{3}{4}of\frac{3}{4}} \right)\) is:

  5. The value of 18 ÷ [26 - {25 - (15 - 5) ÷ 2}] of 12 + 2 - 2 ÷ 4 × 16 is:

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