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Question

Simplify: \(\left\{\frac{16}{36} \div \frac{16}{4}\right\} \div \left(\frac{2}{7} \times \frac{14}{6} + \frac{5}{12}\right) + \frac{4}{7} \div \frac{39}{12} \text{ of } \frac{12}{7}\)

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RRB NTPC 2025 Under Graduate CBT 1 Question Paper PDF (20-Jun-2026) (Shift 3)
The correct answer is

\(\frac{8}{39}\)

Apply BODMAS, resolving of before division. First bracket: \(\frac{16}{36} \div \frac{16}{4} = \frac{16}{36} \times \frac{4}{16} = \frac{4}{36} = \frac{1}{9}\).

Second bracket: \(\frac{2}{7} \times \frac{14}{6} + \frac{5}{12} = \frac{2}{3} + \frac{5}{12} = \frac{8}{12} + \frac{5}{12} = \frac{13}{12}\).

Resolve the of term: \(\frac{39}{12} \text{ of } \frac{12}{7} = \frac{39}{12} \times \frac{12}{7} = \frac{39}{7}\), so \(\frac{4}{7} \div \frac{39}{7} = \frac{4}{7} \times \frac{7}{39} = \frac{4}{39}\).

Now the first division: \(\frac{1}{9} \div \frac{13}{12} = \frac{1}{9} \times \frac{12}{13} = \frac{12}{117} = \frac{4}{39}\).

Add: \(\frac{4}{39} + \frac{4}{39} = \frac{8}{39}\).

Hence, the value of the expression is \(\frac{8}{39}\).

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Important Questions from Bodmas Rule

  1. The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:

  2. The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:

  3. The value of 20 ÷ 5 of 8 × [9 ÷ 6 × (6 - 3)] - (10 ÷ 2 of 20) is:

  4. The value of \(\left( {18 \div 2\;of\frac{1}{4}} \right)\; \times \;\left( {\frac{2}{3} \div \frac{3}{4}\; \times \;\frac{5}{8}} \right) \div \left( {\frac{2}{3} \div \frac{3}{4}of\frac{3}{4}} \right)\) is:

  5. The value of 18 ÷ [26 - {25 - (15 - 5) ÷ 2}] of 12 + 2 - 2 ÷ 4 × 16 is:

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