Simplify: \(\left\{\frac{16}{36} \div \frac{16}{4}\right\} \div \left(\frac{2}{7} \times \frac{14}{6} + \frac{5}{12}\right) + \frac{4}{7} \div \frac{39}{12} \text{ of } \frac{12}{7}\)
\(\frac{8}{39}\)
Apply BODMAS, resolving of before division. First bracket: \(\frac{16}{36} \div \frac{16}{4} = \frac{16}{36} \times \frac{4}{16} = \frac{4}{36} = \frac{1}{9}\).
Second bracket: \(\frac{2}{7} \times \frac{14}{6} + \frac{5}{12} = \frac{2}{3} + \frac{5}{12} = \frac{8}{12} + \frac{5}{12} = \frac{13}{12}\).
Resolve the of term: \(\frac{39}{12} \text{ of } \frac{12}{7} = \frac{39}{12} \times \frac{12}{7} = \frac{39}{7}\), so \(\frac{4}{7} \div \frac{39}{7} = \frac{4}{7} \times \frac{7}{39} = \frac{4}{39}\).
Now the first division: \(\frac{1}{9} \div \frac{13}{12} = \frac{1}{9} \times \frac{12}{13} = \frac{12}{117} = \frac{4}{39}\).
Add: \(\frac{4}{39} + \frac{4}{39} = \frac{8}{39}\).
Hence, the value of the expression is \(\frac{8}{39}\).
Simplify the given expression using BODMAS.
$\frac{4}{11} \times \frac{121}{16} \times 24 (75^2 - 55^2) \times \frac{1}{100}$
The value of 30 ÷ 6 × 5 of (2 + 3) - 12(3 × 2) is equal to:
solve the following:
523 + 523 × 523 ÷ 523
The value of 96 - 4 of (18 - 13) + 4 × 7 is:
Find the value of 45 - 3 × (4 of 6 + 12 ÷ 3 × 6 - 4 × 5) + 6.
The value of \(\frac{{33}}{{40}} + \frac{1}{5}\left[ {\frac{4}{5} - \frac{1}{5} \times \left( {\frac{7}{8} - \frac{5}{4}} \right)} \right] - \frac{4}{5}\) is: