Select the option that is related to the fourth number in the same way as the first number is related to the second number and the fifth number is related to the sixth number. 1008 : 8 :: ? : 6 :: 220 : 4
518
The question presents a number analogy where the relationship between the first and second numbers is the same as the relationship between the fifth and sixth numbers. We need to find the number that shares the same relationship with the fourth number.
The given analogy is: 1008 : 8 :: ? : 6 :: 220 : 4
This can be broken down into three pairs exhibiting the same relationship:
Let's assume the relationship is defined by a function, say \(f(n)\), such that the first/fifth number is the result of applying this function to the second/sixth number. So, we have:
We are looking for a function \(f(n)\) that satisfies \(f(8) = 1008\) and \(f(4) = 220\). Let's try to model this relationship using a polynomial function. Given we have two data points, a linear function (\(f(n) = an + b\)) might be a first guess, but number analogies often involve powers.
Let's consider a quadratic function of the form \(f(n) = an^2 + bn + c\), where \(a\), \(b\), and \(c\) are coefficients we need to find.
Using the given pairs, we can set up the following equations:
We now have a system of two linear equations with three variables. However, we only need to find \(f(6)\). Let's manipulate the equations to find the relationship between \(a\) and \(b\), and express \(c\) in terms of \(a\) and \(b\).
Subtract Equation (2) from Equation (1):
\((64a + 8b + c) - (16a + 4b + c) = 1008 - 220\)
\(48a + 4b = 788\)
Divide by 4:
\(12a + b = 197\)
From this, we can express \(b\) in terms of \(a\):
\(b = 197 - 12a\)
Now substitute the expression for \(b\) into Equation (2) to express \(c\) in terms of \(a\):
\(16a + 4(197 - 12a) + c = 220\)
\(16a + 788 - 48a + c = 220\)
\(-32a + c = 220 - 788\)
\(-32a + c = -568\)
From this, we can express \(c\) in terms of \(a\):
\(c = 32a - 568\)
The missing number is \(f(6)\). Substitute \(n=6\) into the quadratic function \(f(n) = an^2 + bn + c\):
\(f(6) = a(6^2) + b(6) + c = 36a + 6b + c\)
Now substitute the expressions for \(b\) and \(c\) in terms of \(a\) into the equation for \(f(6)\):
\(f(6) = 36a + 6(197 - 12a) + (32a - 568)\)
\(f(6) = 36a + 1182 - 72a + 32a - 568\)
Combine the terms with \(a\) and the constant terms:
\(f(6) = (36a - 72a + 32a) + (1182 - 568)\)
\(f(6) = (-36a + 32a) + 614\)
\(f(6) = -4a + 614\)
We need \(f(6)\) to match one of the given options. Let's test the options by setting \(f(6)\) equal to each option and solving for \(a\). If \(a\) turns out to be a simple value (like an integer or a simple fraction), it suggests we found the correct relationship.
Since \(f(6) = 518\) matches Option 1 and results in reasonable integer coefficients for the quadratic function that fits the other two pairs, this is the correct relationship and missing number.
Let's briefly check other options to confirm they don't yield simple values for \(a\):
Therefore, the relationship is best described by \(f(n) = 24n^2 - 91n + 200\).
The missing number is \(f(6) = 518\).
The relationship connecting the numbers in each pair (First Number : Second Number) is given by the quadratic function \(f(n) = 24n^2 - 91n + 200\), where the First Number is \(f(\text{Second Number})\).
Calculating \(f(6)\):
\(f(6) = 24(6^2) - 91(6) + 200\)
\(f(6) = 24(36) - 546 + 200\)
\(f(6) = 864 - 546 + 200\)
\(f(6) = 318 + 200\)
\(f(6) = 518\)
| Pair | Second Number (n) | First Number (\(f(n)\)) | Pattern Check (\(24n^2 - 91n + 200\)) |
|---|---|---|---|
| 1008 : 8 | 8 | 1008 | \(24(8^2) - 91(8) + 200 = 24(64) - 728 + 200 = 1536 - 728 + 200 = 1008\) |
| ? : 6 | 6 | ? | \(24(6^2) - 91(6) + 200 = 24(36) - 546 + 200 = 864 - 546 + 200 = 518\) |
| 220 : 4 | 4 | 220 | \(24(4^2) - 91(4) + 200 = 24(16) - 364 + 200 = 384 - 364 + 200 = 220\) |
Number analogy questions test your ability to identify mathematical or logical relationships between numbers. Common patterns include:
When solving number analogy problems, it's helpful to:
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