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Question

Related to computers, what is 'Wetware'?

This question was previously asked in
SSC CGL 2016 (Tier 1) Previous Year Question Paper (11-Sep-2016) (Shift 2)
The correct answer is

Human brain

'Wetware' refers to the human brain or the biological elements of computing, distinguishing it from hardware and software. It is a term used to describe the human factors involved in the system.

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Important Questions from Memory Hierarchy

  1. Suppose that the register A and register K have the bit configuration. Only the three leftmost bits of A are compared with memory words because K has 1's in these positions. Because of its organization, this type of memory is uniquely suited to parallel searches by data association. This type of memory is known as

  2. Consider a system with 2 level cache. Access times of Level 1, Level 2 cache and main memory are 0.5 ns, 5 ns and 100 ns respectively. The hit rates of Level 1 and Level 2 caches are 0.7 and 0.8 respectively. What is the average access time of the system ignoring the search time within cache?

  3. ____ number of lines are required to select __________ memory locations.

  4. A computer has a memory hierarchy consisting of two-level cache (L1 and L2) and a main memory. If the processor needs to access data from memory, it first looks into L1 cache. If the data is not found in L1 cache, it goes to L2 cache. If it fails to get the data from L2 cache, it goes to main memory, where the data is definitely available. Hit rates and access times of various memory units are shown in the figure. The average memory access time in nanoseconds (ns) is ________. (rounded off to two decimal places)

  5. Given a computing system with two levels of cache (L1 and L2) and a main memory. The first level (L1) cache access time is 1 nanosecond (ns) and the “hit rate" for L1 cache is 90% while the processor is accessing the data from L1 cache. Whereas, for the second level (L2) cache, the “hit rate" is 80% and the "miss penalty" for transferring data from L2 cache to L1 cache is 10 ns. The “miss penalty" for the data to be transferred from main memory to L2 cache is 100 ns.

    Then the average memory access time in this system in nanoseconds is ____________ (rounded off to one decimal place)
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