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Question

Refer to the following series and answer the question. (Counting to be done from left to right only. Note: All numbers are single digit numbers only) (Left) 4 5 6 9 1 6 1 9 5 5 8 8 5 9 5 7 1 5 7 8 5 3 5 4 3 2 9 4 6 6 (Right) How many such even digits are there each of the which is immediately preceded by a perfect square and immediately followed by an odd digit? (NOTE: 1 is also a perfect square)

This question was previously asked in
RRB Group D 2025 Question Paper (18-Aug-2026) (Shift 1)
The correct answer is

One

Scan the series 4 5 6 9 1 6 1 9 5 5 8 8 5 9 5 7 1 5 7 8 5 3 5 4 3 2 9 4 6 6 from left to right.

Look at each even digit and check whether the digit just before it is a perfect square (1, 4 or 9) and the digit just after it is odd.

The triplet 1 6 1 (positions 5-6-7): preceded by 1 (perfect square) and followed by 1 (odd) — qualifies.

Other candidate even digits fail one of the two conditions: for example, 9 4 6 has an even digit 6 after 4, but 4 (perfect square) is followed by 6 (even), so 4-6 fails the ‘odd after’ check.

Only one even digit meets both conditions.

Hence, the count is One.

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