Ratio of the present age of a mother to that of the daughter is 7 ∶ 1. After 5 years the ratio will become 4 ∶ 1. What is the difference (in years) in their present ages?
30
Given:
The current age ratio of mother and daughter = 7 : 1
After 5 years, the ratio will be = 4 : 1
Calculation:
Let the current age be x.
Then,
According to the given question
⇒ (7x + 5)/(x + 5) = 4/1
⇒ 7x + 5 = 4x + 20
⇒ 3x = 15
⇒ x = 5
Mother's current age = 7x = 7 × 5 = 35 years
Daughter's current age = x = 5 years
Required difference = (35 – 5) = 30 years
∴ The difference in their current ages is 30 years.
The ratio of present ages of A and B is 7 : 8. After 6 years from now, the ratio of their ages will be 8 : 9. If C's present age is 10 years more than the present age of A, then the present age (in years) of C is:
Three years ago, the ratio of the age of father to that of his son was 8 ∶ 3. After 4 years, their ages will be in the ratio 11 ∶ 5. What is the present age (in years) of the father?
At present, A is younger than B by 8 years. If 4 years ago, their ages were in the ratio 1 ∶ 2, then what is the present age of B (in years)?
Eight years ago, the ratio of ages of A and B was 5 ∶ 4. The ratio of their present ages is 6 ∶ 5. What will be the sum (in years) of the ages of A and B after 7 years from now?
The sum of the presents age of a father and son is 52 years Four years hence, the son's age will be 1/4 that of the father. What will be the ratio of the age of the son and father, 10 years from now?