At present, A is younger than B by 8 years. If 4 years ago, their ages were in the ratio 1 ∶ 2, then what is the present age of B (in years)?
20
This problem involves the ages of two people, A and B, at different points in time: the present and 4 years ago. We are given the age difference between them now and the ratio of their ages 4 years ago. Our goal is to find the present age of B.
Let's use variables to represent their present ages:
We are given two conditions:
Let's translate these conditions into mathematical equations.
A is 8 years younger than B. This means the difference between B's age and A's age is 8 years.
\(B - A = 8\)
We can express A's age in terms of B's age from this equation:
\(A = B - 8\) (Equation 1)
First, let's determine their ages 4 years ago:
The ratio of their ages 4 years ago was 1 ∶ 2. This can be written as a fraction:
\(\frac{A - 4}{B - 4} = \frac{1}{2}\) (Equation 2)
Now we have a system of two equations with two variables (\(A\) and \(B\)):
We can substitute the expression for \(A\) from Equation 1 into Equation 2.
Substitute \(A = B - 8\) into \(\frac{A - 4}{B - 4} = \frac{1}{2}\):
\(\frac{(B - 8) - 4}{B - 4} = \frac{1}{2}\)
Simplify the numerator:
\(\frac{B - 12}{B - 4} = \frac{1}{2}\)
Now, we can cross-multiply to solve for \(B\):
\(2 \times (B - 12) = 1 \times (B - 4)\)
\(2B - 24 = B - 4\)
Collect the \(B\) terms on one side and the constant terms on the other side:
\(2B - B = 24 - 4\)
\(B = 20\)
So, the present age of B is 20 years.
Let's check if this value of B satisfies the original conditions.
Simplify the ratio \(8:16\) by dividing both numbers by their greatest common divisor, which is 8:
\(\frac{8}{8} : \frac{16}{8} = 1 : 2\)
The ratio 4 years ago is 1:2, which matches the second condition given in the problem. The age difference now is \(20 - 12 = 8\), which matches the first condition.
Both conditions are satisfied, confirming that the present age of B is 20 years.
The present age of B is 20 years.
| Step | Description | Application in this Problem |
|---|---|---|
| 1 | Define variables for present ages. | Let A's present age = \(A\), B's present age = \(B\). |
| 2 | Translate present age conditions into equations. | A is 8 yrs younger than B → \(B - A = 8\). |
| 3 | Express past/future ages using the defined variables. | 4 years ago: A's age = \(A - 4\), B's age = \(B - 4\). |
| 4 | Translate past/future age conditions (like ratios) into equations. | Ratio 4 yrs ago was 1:2 → \(\frac{A - 4}{B - 4} = \frac{1}{2}\). |
| 5 | Solve the system of equations. | Substitute \(A = B - 8\) into the ratio equation and solve for \(B\). |
| 6 | Verify the solution with the original conditions. | Check if A's age (\(B-8\)) and the past ages satisfy the ratio. |
Age problems are common in quantitative aptitude. They typically involve setting up linear equations based on given conditions about ages at different times (past, present, future).
Ratio problems, like the one discussed, often lead to fractional equations that can be solved by cross-multiplication.
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