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Question

OA BC is a parallelogram. If \( \overrightarrow{OB} = \vec{a} \) and \( \overrightarrow{AC} = \vec{b} \), then \( \overrightarrow{OA} \) is equal to:

The correct answer is

\( \frac{\vec{a} - \vec{b}}{2} \)

In a parallelogram, the midpoint of the diagonals is the same.

From the given vectors, we find that \( O \) and \( A \) are positioned such that:

\( \overrightarrow{OA} = \frac{\overrightarrow{OB} + \overrightarrow{OC}}{2} \).

Since \( \overrightarrow{OC} = \overrightarrow{OB} - \overrightarrow{AC} = \vec{a} - \vec{b} \), we get:

\( \overrightarrow{OA} = \frac{\vec{a} - \vec{b}}{2} \).

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