In Hershey and Chase experiment, some viruses grew on medium that contained:
35S, 32P
Hershey and Chase labeled bacteriophages with:
1. 35S: Labeled sulfur to mark proteins, as sulfur is present in proteins but not in DNA.
2. 32P: Labeled phosphorus to mark DNA, as phosphorus is a component of DNA but not proteins.
Their experiment demonstrated that only DNA entered bacterial cells during infection, proving DNA is the genetic material.
Match List-I with List-II:
List-I (Scientists)
List-II (Discovery)
| List-I | List-II |
|---|---|
| (A) Sutton and Boveri | (I) X-Body |
| (B) Sturtevant | (II) Chromosomal Theory of Inheritance |
| (C) Henking | (III) Transformation in bacteria |
| (D) Griffith | (IV) Genetic maps |
Choose the correct answer from the options given below:
Which of the following statements are incorrect with respect to nucleotides?
(A) Purines and pyrimidines are nitrogenous bases.
(B) Nucleotides are non-enzymatic molecules.
(C) Phosphate group is linked to –OH of 5' C of a nucleoside through phosphoester linkage.
(D) In RNA, every nucleotide residue has an additional –OH group present at 2' position in the ribose.
(E) Thymine is an example of pyrimidine.
Arrange the given steps of DNA fingerprinting in the sequence from initiation to end:
(A) Digestion of DNA by restriction endonuclease
(B) Isolation of DNA
(C) Hybridisation using labelled VNTR probe
(D) Transferring (blotting) of separated DNA fragments to synthetic membrane
Nucleosome is associated with _______ molecules of histones.
Select the observations drawn from the human genome project which are correct:
(A) The human genome contains 3164.7 million bp.
(B) The average gene consists of 3000 bases.
(C) Total number of genes is estimated at 30,000.
(D) The functions are unknown for over 50% of discovered genes.
(E) Less than 2% of the genome codes for proteins.
Arrange the following steps of DNA fingerprinting in proper sequence:
(A) Hybridisation using labelled VNTR probe
(B) Separation of DNA fragments by electrophoresis
(C) Digestion of DNA by restriction endonucleases
(D) Blotting of separated DNA fragments to nylon
(E) Isolation of DNA
Choose the correct answer from the options given below:
Nucleosome is:
“Transforming Principle” was given by:
Select the incorrect statement:
Match List-I with List-II:
| List-I (Genes) | List-II (Proteins – codes for lac operon) |
|---|---|
| (A) ‘i’ | (I) permease |
| (B) ‘a’ | (II) β-galactosidase |
| (C) ‘y’ | (III) transacetylase |
| (D) ‘z’ | (IV) repressor |
Choose the correct answer from the options given below:
What will be the chromosome number in the gamete of fruit fly if its meiocyte has 8 chromosomes?
Match List-I with List-II:
| List-I (Organism) | List-II (Sex Chromosomes) |
|---|---|
| (A) Male grasshopper | (I) XY |
| (B) Male Drosophila | (II) XX |
| (C) Female bird | (III) XX |
| (D) Female grasshopper | (IV) XO |
Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) Bacteriophage lambda | (I) 231 gene |
| (B) Y-chromosome of human | (II) 48502 bp |
| (C) Haploid content of human DNA | (III) 3.3 × 109 bp |
| (D) Escherichia coli DNA | (IV) 4.6 × 106 bp |
Choose the correct answer from the options given below:
Central dogma in molecular biology states that genetic information flows from:
Read the following and select the set of correct statements. (A) Euchromatin is transcriptionally inactive (B) Heterochromatin is more densely packed (C) Heterochromatin is loosely packed (D) Euchromatin is transcriptionally active (E) Euchromatin stains lighter