Nucleosome is:
Negatively charged DNA wrapped around positively charged histone octamer
A nucleosome represents the fundamental structural unit of chromatin in eukaryotic cells. Think of it as the basic bead on a string, where the 'string' is the DNA and the 'bead' is a complex of proteins called the histone octamer. This packaging is essential to fit the long DNA molecule into the cell nucleus.
A nucleosome is composed of two main parts:
DNA is a negatively charged molecule. This negative charge comes from the phosphate groups present in the sugar-phosphate backbone of each nucleotide. The formula for a phosphate group is $\text{PO}_4^{3-}$, and in DNA, it typically carries a charge of $-1$ after protonation states in physiological conditions.
The histone octamer is a complex formed by eight histone proteins: two molecules each of H2A, H2B, H3, and H4. Histone proteins are rich in basic amino acids, particularly lysine and arginine. These amino acids have side chains that are positively charged at physiological pH. This abundance of positively charged amino acids makes the histone octamer as a whole positively charged.
The negatively charged DNA molecule is attracted to and wraps around the positively charged histone octamer. This electrostatic attraction between opposite charges is crucial for the stable formation of the nucleosome structure. Approximately 146 base pairs of DNA wrap around the histone octamer.
Let's examine the given options based on our understanding of DNA and histone charges:
Therefore, the description that accurately defines a nucleosome based on the charges of its components is negatively charged DNA wrapped around a positively charged histone octamer.
| Component | Description | Electric Charge |
|---|---|---|
| DNA | Double helix molecule carrying genetic information | Negatively charged (due to phosphate groups) |
| Histone Octamer | Complex of 8 histone proteins (2x H2A, 2x H2B, 2x H3, 2x H4) | Positively charged (due to basic amino acids like lysine & arginine) |
| Nucleosome | Basic unit of chromatin; DNA wrapped around histone octamer | Overall neutral or slightly negative (charge depends on modifications), but the interaction is based on opposite charges of DNA and histone octamer. |
The formation of nucleosomes is the first level of DNA packaging in eukaryotes. The 'string' connecting adjacent nucleosome 'beads' is called linker DNA, associated with histone H1. These nucleosomes are further coiled and folded into more complex structures, eventually forming chromosomes visible during cell division. This hierarchical packaging allows the vast amount of DNA to fit into the confined space of the nucleus.
Arrange the following steps of DNA fingerprinting in proper sequence:
(A) Hybridisation using labelled VNTR probe
(B) Separation of DNA fragments by electrophoresis
(C) Digestion of DNA by restriction endonucleases
(D) Blotting of separated DNA fragments to nylon
(E) Isolation of DNA
Choose the correct answer from the options given below:
“Transforming Principle” was given by:
Select the incorrect statement:
Match List-I with List-II:
| List-I (Genes) | List-II (Proteins – codes for lac operon) |
|---|---|
| (A) ‘i’ | (I) permease |
| (B) ‘a’ | (II) β-galactosidase |
| (C) ‘y’ | (III) transacetylase |
| (D) ‘z’ | (IV) repressor |
Choose the correct answer from the options given below:
Amino acid is attached to which site of tRNA?
Given below is the DNA coding sequence. Its complementary strand would read as:
5′ – GTATTACG – 3′
The size of VNTR varies from:
In which phase of the cell cycle does replication of DNA take place?
In Hershey and Chase experiment, some viruses grew on medium that contained:
Who performed experiments on Vicia faba to prove that DNA replicates semi-conservatively?
What will be the chromosome number in the gamete of fruit fly if its meiocyte has 8 chromosomes?
Match List-I with List-II:
| List-I (Organism) | List-II (Sex Chromosomes) |
|---|---|
| (A) Male grasshopper | (I) XY |
| (B) Male Drosophila | (II) XX |
| (C) Female bird | (III) XX |
| (D) Female grasshopper | (IV) XO |
Choose the correct answer from the options given below:
Match List-I with List-II:
| List-I | List-II |
|---|---|
| (A) Bacteriophage lambda | (I) 231 gene |
| (B) Y-chromosome of human | (II) 48502 bp |
| (C) Haploid content of human DNA | (III) 3.3 × 109 bp |
| (D) Escherichia coli DNA | (IV) 4.6 × 106 bp |
Choose the correct answer from the options given below:
Central dogma in molecular biology states that genetic information flows from:
Read the following and select the set of correct statements. (A) Euchromatin is transcriptionally inactive (B) Heterochromatin is more densely packed (C) Heterochromatin is loosely packed (D) Euchromatin is transcriptionally active (E) Euchromatin stains lighter