Nitin departs from his home and walks 45 m towards the east. He then turns left and walks 48 m. He turns left again and walks 27 m. He takes a final left turn and walks 55 m. How far is he from a pole which is exactly 7 m to the south of his home? (Assume that all the turns are 90° turns only.)
18 m
This problem involves tracking a person's movement through a series of turns and calculating their final distance from a specific point. We will use a coordinate system approach to solve this efficiently. Let's assume Nitin's home is the origin (0,0).
We need to break down Nitin's journey step by step:
We are asked to find the distance between his final position and a pole located 7 m south of his home.
Let's track Nitin's position using coordinates, assuming East is along the positive x-axis and North is along the positive y-axis.
Nitin's final position is (18, -7) relative to his home at (0,0).
The problem states that the pole is exactly 7 m to the south of his home. Since home is at (0,0) and South is the negative y direction, the pole's coordinates are (0, 0 - 7) = (0, -7).
Pole's Position = (0, -7).
Nitin's final position is (18, -7).
The pole's position is (0, -7).
We need to find the distance between these two points. We can use the distance formula, or notice that both points have the same y-coordinate (-7). This means they lie on the same horizontal line (at y = -7). The distance between them is simply the absolute difference in their x-coordinates.
Distance = $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$
Let $(x_1, y_1) = (18, -7)$ and $(x_2, y_2) = (0, -7)$.
Distance = $\sqrt{(0 - 18)^2 + (-7 - (-7))^2}$
Distance = $\sqrt{(-18)^2 + (0)^2}$
Distance = $\sqrt{324 + 0}$
Distance = $\sqrt{324}$
Distance = 18
Alternatively, since the y-coordinates are the same:
Distance = $|x_2 - x_1| = |0 - 18| = |-18| = 18$ m.
The distance between Nitin's final position and the pole is 18 m.
| Movement | Direction | Distance (m) | Change in X (m) | Change in Y (m) | Current Position (x, y) |
|---|---|---|---|---|---|
| Start | - | - | - | - | (0, 0) |
| 1st Leg | East (+x) | 45 | +45 | 0 | (45, 0) |
| 2nd Leg | Left (North, +y) | 48 | 0 | +48 | (45, 48) |
| 3rd Leg | Left (West, -x) | 27 | -27 | 0 | (18, 48) |
| 4th Leg | Left (South, -y) | 55 | 0 | -55 | (18, -7) |
| Point | X-coordinate | Y-coordinate |
|---|---|---|
| Nitin's Final Position | 18 | -7 |
| Pole's Position | 0 | -7 |
The distance between (18, -7) and (0, -7) is the difference in their x-coordinates, which is 18 - 0 = 18.
So, Nitin is 18 m away from the pole.
Understanding directions and turns is crucial for these types of problems:
| Current Direction | Left Turn | Right Turn |
|---|---|---|
| North (+y) | West (-x) | East (+x) |
| South (-y) | East (+x) | West (-x) |
| East (+x) | North (+y) | South (-y) |
| West (-x) | South (-y) | North (+y) |
Using a coordinate system (like the Cartesian plane) is a powerful method for solving direction and distance problems. We assign directions to axes (e.g., East = +x, North = +y). Each movement can then be represented as a change in the x or y coordinate. The final position is a single point (x, y). The distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ can be found using the distance formula derived from the Pythagorean theorem:
Distance = $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$
In cases where the x-coordinates are the same ($x_1 = x_2$), the distance is $|y_2 - y_1|$.
In cases where the y-coordinates are the same ($y_1 = y_2$), the distance is $|x_2 - x_1|$.
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