Lalit walks 9 km east, turns left and walks another 8 km. He again takes a left and walks another 3 km. How far and in which direction is he now from his starting point?
10 km, north east
This question asks us to find the final position of Lalit relative to his starting point after a series of movements in different directions. We need to determine both the straight-line distance and the direction from the start.
Let's break down Lalit's journey:
We can analyze the movements along the East-West axis and the North-South axis separately.
So, from his starting point, Lalit's final position is 6 km to the East and 8 km to the North.
The net movements form the two perpendicular sides of a right-angled triangle. The displacement (straight-line distance from the start) is the hypotenuse of this triangle. We can use the Pythagorean theorem to find this distance.
Let:
According to the Pythagorean theorem:
\( D^2 = (\Delta x)^2 + (\Delta y)^2 \)
Substituting the values:
\( D^2 = (6 \, \text{km})^2 + (8 \, \text{km})^2 \)
\( D^2 = 36 \, \text{km}^2 + 64 \, \text{km}^2 \)
\( D^2 = 100 \, \text{km}^2 \)
To find \( D \), we take the square root of both sides:
\( D = \sqrt{100 \, \text{km}^2} \)
\( D = 10 \, \text{km} \)
The distance from the starting point is 10 km.
Since the final position is 6 km East and 8 km North of the starting point, the direction is a combination of North and East. This direction is known as North East.
Lalit is 10 km away from his starting point in the North East direction.
Comparing this with the given options, we find:
| Option | Distance & Direction | Matches Calculation? |
|---|---|---|
| 1 | 14 km, south east | No |
| 2 | 12 km, north west | No |
| 3 | 8 km, south west | No |
| 4 | 10 km, north east | Yes |
| Concept | Description | How it applies here |
|---|---|---|
| Cardinal Directions | North, South, East, West. | Used to define movement axes. |
| Turns (Left/Right) | Change in facing direction (usually 90 degrees). | Determines the direction of the next segment of walk. |
| Displacement | Shortest straight-line distance from start to end point. Vector quantity. | What the question asks for (distance and direction from start). |
| Pythagorean Theorem | \( a^2 + b^2 = c^2 \) for a right-angled triangle. | Used to calculate the displacement distance when net movements are perpendicular. |
Direction and distance questions often involve visualizing movements on a plane. Here are some tips:
Understanding turns is crucial:
Starting from her home, a woman walks 10 km towards the west. She turns left and walks 25 km. Again she turns left and walks 10 km. After that, she again turns left and walks 5 km. How far is she from her house now?
A. 35
B. 20
C. 25
D. 40
A boy starts from his home northward in order to go to a hotel. He took right turn and took left to reach the hotel. Which direction is the hotel facing?
Arun went 6 m from his home towards south and turned left to cover 8 m. Again he turned left and covered 6 m. He again turned right and covered 4 m. What was the direct distance from his home and which direction was he facing?
Sri walked 4 km towards east from home to school, and he turned three times right side of 6 km respectively. What is the distance between his home and the school?
Uday starts from Point Y and drives 16 km towards the North. He then takes a right turn, drives 28 km, turns right and drives 31 km. He then takes a right turn and drives 13 km. He takes a right turn and drives 41 km. He then turns left, drives 15 km, turns right and drives 8 km to stop at Point Z. How far (shortest distance) and towards which direction should he drive in order to reach Point Y again? (All turns are 90-degree turns only unless specified)