This problem involves calculating the day Mohan achieves a specific savings target based on a daily earning and spending pattern. We need to find the day he reaches ₹200 just after earning, but before spending.
Consider a 2-day cycle (one earning day + one spending day):
Mohan's savings increase by ₹10 every 2 days.
The target is to have ₹200 *before spending*. This means the amount should reach ₹200 after Mohan earns on an odd-numbered day.
Let the day be 'D'. On day 'D', he earns ₹60. The amount he had at the end of the previous day (Day D-1) plus ₹60 must equal ₹200.
Amount at end of Day (D-1) + $60 = 200$
Amount at end of Day (D-1) = $200 - 60 = 140$ rupees.
So, Mohan needs to accumulate ₹140 by the end of an even-numbered day (the day before he hits the target).
Since the net gain is ₹10 per 2-day cycle, the number of cycles needed to reach ₹140 is:
Number of Cycles = $\frac{\text{Target amount before earning}}{\text{Net gain per cycle}} = \frac{140}{10} = 14$ cycles.
Each cycle consists of 2 days. Therefore, 14 cycles will take:
Total Days = $14 \text{ cycles} \times 2 \text{ days/cycle} = 28$ days.
At the end of the 28th day (after spending ₹50), Mohan will have ₹140.
The day after the 28th day is the 29th day. Day 29 is an earning day.
On the 29th day, Mohan earns ₹60.
His total money becomes: ₹140 (from end of Day 28) + ₹60 (earned on Day 29) = ₹200.
This amount is achieved *before* he spends on Day 29, fulfilling the condition.
Mohan will have ₹200 with him on the $29^{\text{th}}$ day before spending.
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