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Question

Match the following :

List – IList – II  
a. Snubber circuiti. SCR
b. Inverterii. High efficiency
c. Phase controliii. \(\dfrac{dv}{dt}\) protection
d. SMPSiv. UJT

Codes :

This question was previously asked in
UGC NET 2014 Paper 2 History Question Paper (28-Dec-2014)
The correct answer is

a-iii, b-i, c-iv, d-ii

 Two pairings are textbook definitions and they carry the rest: a-iii, b-i, c-iv, d-ii — option 1.

ItemMatch
a. Snubber circuitiii. dv/dt protection
b. Inverteri. SCR
c. Phase controliv. UJT
d. SMPSii. High efficiency

a — what the snubber protects against. A thyristor's internal junctions have capacitance. A rapidly rising anode voltage drives a displacement current through it,

\(i=C_{j}\dfrac{dv}{dt}\)

and if that current is large enough it acts like gate current and turns the device on when no trigger was applied — a false firing that can short the supply. An RC snubber across the device gives that current a path through the capacitor instead, slowing the rate of rise the junction sees; the series resistor limits the discharge current when the device does turn on legitimately.

b — the inverter and the SCR. An inverter turns DC into AC by switching, and thyristors are the classic switching element for high-power inverters. The difficulty is that an SCR on a DC supply has no natural current zero at which to turn off, so forced commutation is needed — an auxiliary LC circuit that drives the anode current briefly to zero. That complication is the whole reason GTOs and IGBTs displaced SCRs in medium-power inverters.

c — the UJT and phase control. Controlling AC power by delaying the firing angle needs a pulse at a precisely adjustable point in each half cycle. A unijunction transistor relaxation oscillator produces exactly that: a capacitor charges through a variable resistor until the emitter reaches the peak point,

\(V_{P}=\eta V_{BB}+V_{D}\)

whereupon the UJT fires and dumps the charge into the thyristor's gate as a sharp pulse. Turning the resistor moves the firing angle and so the delivered power.

d — why a switched-mode supply is efficient. A linear regulator's pass transistor is in the active region continuously, dropping the excess voltage and dissipating it as heat — efficiency of perhaps 40 %. An SMPS switches its transistor fully on or fully off. When on, the voltage across it is nearly zero; when off, the current through it is nearly zero; and power is the product, so dissipation is small in both states. Efficiencies of 85 to 95 % follow, and the high switching frequency also allows a much smaller transformer.

Hence, the correct code is a-iii, b-i, c-iv, d-ii.

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Similar Questions

  1. An SCR has half cycle surge current rating of 3000 A for 50 Hz supply. It has

    A. one cycle surge current = 2121.32 A

    B. One cycle surge current = 1121.32 A

    C. I2t rating = 45000 Amp2

    D. I2t rating = 1257358 Amp2

    Choose the correct answer from the options given below:

  2. In thyristor \(\dfrac{di}{dt}\) failure is prevented by

  3. Assertion (A) : A number of thyristors operating in parallel cannot share a common heatsink.

    Reason (R) : For simultaneous firing of the thyristor opto-isolator may be employed in the gate driving circuit.


Important Questions from Thyristor Protection

  1. Which of the following is a safety device connected in series to the circuit?

  2. What is the term for the minimum anode current below which a thyristor will turn OFF and stay OFF, even if a gate pulse was previously applied?

  3. The Snubber circuit is used to thyristor circuits for -

  4. For series connected SCRs, static equalization is obtained with the help of

  5. Which of the following is the function of an R-C snubber circuit connected in parallel to an SCR?

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