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Question

Match the following :

List – IList – II  
a. Snubber circuiti. SCR
b. Inverterii. High efficiency
c. Phase controliii. \(\dfrac{dv}{dt}\) protection
d. SMPSiv. UJT

Codes :

This question was previously asked in
UGC NET 2014 Paper 1 Question Paper (28-Dec-2014)
The correct answer is

a-iii, b-i, c-iv, d-ii

 Two pairings are textbook definitions and they carry the rest: a-iii, b-i, c-iv, d-ii — option 1.

ItemMatch
a. Snubber circuitiii. dv/dt protection
b. Inverteri. SCR
c. Phase controliv. UJT
d. SMPSii. High efficiency

a — what the snubber protects against. A thyristor's internal junctions have capacitance. A rapidly rising anode voltage drives a displacement current through it,

\(i=C_{j}\dfrac{dv}{dt}\)

and if that current is large enough it acts like gate current and turns the device on when no trigger was applied — a false firing that can short the supply. An RC snubber across the device gives that current a path through the capacitor instead, slowing the rate of rise the junction sees; the series resistor limits the discharge current when the device does turn on legitimately.

b — the inverter and the SCR. An inverter turns DC into AC by switching, and thyristors are the classic switching element for high-power inverters. The difficulty is that an SCR on a DC supply has no natural current zero at which to turn off, so forced commutation is needed — an auxiliary LC circuit that drives the anode current briefly to zero. That complication is the whole reason GTOs and IGBTs displaced SCRs in medium-power inverters.

c — the UJT and phase control. Controlling AC power by delaying the firing angle needs a pulse at a precisely adjustable point in each half cycle. A unijunction transistor relaxation oscillator produces exactly that: a capacitor charges through a variable resistor until the emitter reaches the peak point,

\(V_{P}=\eta V_{BB}+V_{D}\)

whereupon the UJT fires and dumps the charge into the thyristor's gate as a sharp pulse. Turning the resistor moves the firing angle and so the delivered power.

d — why a switched-mode supply is efficient. A linear regulator's pass transistor is in the active region continuously, dropping the excess voltage and dissipating it as heat — efficiency of perhaps 40 %. An SMPS switches its transistor fully on or fully off. When on, the voltage across it is nearly zero; when off, the current through it is nearly zero; and power is the product, so dissipation is small in both states. Efficiencies of 85 to 95 % follow, and the high switching frequency also allows a much smaller transformer.

Hence, the correct code is a-iii, b-i, c-iv, d-ii.

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Similar Questions

  1. In thyristor \(\dfrac{di}{dt}\) failure is prevented by

  2. Assertion (A) : A number of thyristors operating in parallel cannot share a common heatsink.

    Reason (R) : For simultaneous firing of the thyristor opto-isolator may be employed in the gate driving circuit.

  3. An SCR has half cycle surge current rating of 3000 A for 50 Hz supply. It has

    A. one cycle surge current = 2121.32 A

    B. One cycle surge current = 1121.32 A

    C. I2t rating = 45000 Amp2

    D. I2t rating = 1257358 Amp2

    Choose the correct answer from the options given below:


Important Questions from Thyristor Protection

  1. Match List-I with List-II and select the correct answer using the given lists:

    List – I

    (SCR rating)

    List – II

    (Protective element)

    A. di/dt limit

    1. Snubber

    B. dV/dt limit

    2. Heat sink

    C. i2t limit

    3. Series reactor

    D. Junction temperature limit

    4. Avoid runway speed on no load

  2. Which of the following is the function of an R-C snubber circuit connected in parallel to an SCR?

  3. For series connected SCRs, static equalization is obtained with the help of

  4. The Snubber circuit is used to thyristor circuits for -

  5. In thyristor \(\dfrac{di}{dt}\) failure is prevented by

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