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Question

In thyristor \(\dfrac{di}{dt}\) failure is prevented by

This question was previously asked in
UGC NET 2014 Paper 1 Question Paper (28-Dec-2014)
The correct answer is

putting L in series with anode

 An inductor is the one element that opposes a change of current, so a series inductance in the anode lead limits di/dt — option 1.

\(v=L\dfrac{di}{dt}\quad\Rightarrow\quad \dfrac{di}{dt}=\dfrac{v}{L}\)

The larger the inductance, the more slowly the current can rise for a given applied voltage, so L is chosen to keep di/dt below the manufacturer's rating.

Why an excessive di/dt destroys the device. When the gate fires an SCR, conduction does not begin over the whole junction at once. It starts in a small area next to the gate contact and spreads outward at only about 0.1 mm per microsecond. If the external circuit forces the full load current before the conducting region has spread, the entire current is crowded into that tiny area; the local current density becomes enormous, the temperature there rises far above the rest of the die, and a local hot spot melts the silicon. The device fails even though the average current is well within its rating.

StressProtectionWhy
di/dtSeries L in the anodeOpposes rate of rise of current
dv/dtRC snubber across the SCRDiverts the capacitive charging current

The parallel problem, which explains the distractors. A thyristor is also vulnerable to a rapid rise of voltage: displacement current through its internal junction capacitance, \(i=C_{j}\,dv/dt\), can act like gate current and turn the device on when no trigger was applied. The remedy there is an RC snubber — but it goes in parallel with the SCR, not in series. Options 3 and 4 borrow the snubber's components and put them in the wrong place, where a series capacitor would simply block the load current altogether.

Option 2 is wrong for a different reason. A series resistor limits the magnitude of the current, not its rate of rise — and it dissipates power continuously, which is unacceptable in a converter handling large currents.

In practice the two protections are used together: a saturable reactor or small air-cored inductor in series for di/dt, and an RC snubber across the device for dv/dt, since a converter subjects the thyristor to both stresses at every commutation.

Hence, di/dt failure is prevented by putting L in series with the anode.

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Similar Questions

  1. Match the following :

    List – IList – II  
    a. Snubber circuiti. SCR
    b. Inverterii. High efficiency
    c. Phase controliii. \(\dfrac{dv}{dt}\) protection
    d. SMPSiv. UJT

    Codes :

  2. Assertion (A) : A number of thyristors operating in parallel cannot share a common heatsink.

    Reason (R) : For simultaneous firing of the thyristor opto-isolator may be employed in the gate driving circuit.

  3. An SCR has half cycle surge current rating of 3000 A for 50 Hz supply. It has

    A. one cycle surge current = 2121.32 A

    B. One cycle surge current = 1121.32 A

    C. I2t rating = 45000 Amp2

    D. I2t rating = 1257358 Amp2

    Choose the correct answer from the options given below:


Important Questions from Thyristor Protection

  1. Match List-I with List-II and select the correct answer using the given lists:

    List – I

    (SCR rating)

    List – II

    (Protective element)

    A. di/dt limit

    1. Snubber

    B. dV/dt limit

    2. Heat sink

    C. i2t limit

    3. Series reactor

    D. Junction temperature limit

    4. Avoid runway speed on no load

  2. Which of the following is the function of an R-C snubber circuit connected in parallel to an SCR?

  3. For series connected SCRs, static equalization is obtained with the help of

  4. The Snubber circuit is used to thyristor circuits for -

  5. Match the following :

    List – IList – II  
    a. Snubber circuiti. SCR
    b. Inverterii. High efficiency
    c. Phase controliii. \(\dfrac{dv}{dt}\) protection
    d. SMPSiv. UJT

    Codes :

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