This problem involves calculating the final amount Mahesh will receive from a fixed deposit after 2 years, considering compound interest.
The formula to calculate the amount ($A$) on maturity with compound interest is:
$A = P \times (1 + \frac{r}{100})^n$
$A = 8000 \times (1 + \frac{5}{100})^2$
$1 + \frac{5}{100} = 1 + 0.05 = 1.05$
So the formula becomes:
$A = 8000 \times (1.05)^2$
$(1.05)^2 = 1.1025$
Now the formula is:
$A = 8000 \times 1.1025$
$A = 8820$
Mahesh will receive ₹8820 on the maturity of the fixed deposit.
At what rate percent per annum will Rs. 7200 amount to Rs. 7938 in one year, if interest is compounded half yearly?
What is the compound interest (in Rs.) on a sum of Rs. 8192 for \(1 \frac{1}{4}\) years at 15% per annum, if interest is compounded 5-monthly ?
What is the difference (in Rs.) between the interests on Rs. 50,000 for one year at 8% per annum compounded half yearly and yearly?
A sum of money becomes Rs. 11,880 after 4 years and Rs. 17,820 after 6 years on compound interest, if the interest is compounded annually. What is the half of the sum (in Rs.)?
A sum invested at compound interest amounts to Rs. 7,800 in 3 years and Rs. 11,232 in 5 years. What is the rate per cent?