The problem involves calculating the rate of compound interest given the interest earned in two consecutive years.
In compound interest, the interest earned in one year is added to the principal for the next year. The difference between the interest amounts of two successive years represents the interest earned on the previous year's interest.
The difference (₹11.25) is the interest calculated on the first year's interest (₹225) at the given rate (R). We can express this using the simple interest formula for one year:
Interest = Principal × Rate / 100
In this case:
₹11.25 = ₹225 × R / 100
Rearrange the formula to solve for R:
R = (₹11.25 × 100) / ₹225
R = 1125 / 225
R = 5
Therefore, the rate of interest is 5%.
Find the total amount (in ₹) on ₹4500 at 12% per annum for 2 years and 8 months compounded annually.
A sum of money becomes $₹6,400$ in $2\text{ years}$ and $₹8,100$ in $4\text{ years}$ on compound interest. Find the rate of compound interest.
A person borrowed Rs. 10000 on compound interest at the rate of 40 percent per annum. If the interest is compounded half yearly, then what will be the amount to be paid after 1.5 years?
The difference between the compound interest (compounding annually) and the simple interest on a sum of money at the rate of 40 per cent per annum for 2 years is Rs. 2400. What is the amount?
In how many years will a sum of Rs.1875 amount to Rs.2187 at 8 percent p.a. compound interest?
A sum of money has increased by 45% in 9 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?
At a certain rate of compound interest a certain sum amounts to Rs. 64800 in 4 years and Rs. 93312 in 6 years. What is the compound interest earned in fifth year?