A sum of money becomes $₹6,400$ in $2\text{ years}$ and $₹8,100$ in $4\text{ years}$ on compound interest. Find the rate of compound interest.
Let the principal amount be $P$ and the annual compound interest rate be $r$. The formula for the amount $A$ after $t$ years is given by $A = P(1 + r)^t$.
From the given information, we can write two equations:
To find the rate $r$, divide the second equation by the first equation:
$ \frac{8100}{6400} = \frac{P(1 + r)^4}{P(1 + r)^2} $
Simplify the equation:
$ \frac{81}{64} = (1 + r)^{4-2} $
$ \frac{81}{64} = (1 + r)^2 $
Take the square root of both sides:
$ \sqrt{\frac{81}{64}} = 1 + r $
$ \frac{9}{8} = 1 + r $
Now, solve for $r$:
$ r = \frac{9}{8} - 1 $
$ r = \frac{9 - 8}{8} $
$ r = \frac{1}{8} $
Convert the rate to a percentage:
$ r = \frac{1}{8} \times 100\% $
$ r = 12.5\% $
The rate of compound interest is $12.5\%$.
Find the total amount (in ₹) on ₹4500 at 12% per annum for 2 years and 8 months compounded annually.
A person borrowed Rs. 10000 on compound interest at the rate of 40 percent per annum. If the interest is compounded half yearly, then what will be the amount to be paid after 1.5 years?
The difference between the compound interest (compounding annually) and the simple interest on a sum of money at the rate of 40 per cent per annum for 2 years is Rs. 2400. What is the amount?
In how many years will a sum of Rs.1875 amount to Rs.2187 at 8 percent p.a. compound interest?
A sum of money has increased by 45% in 9 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?
At a certain rate of compound interest a certain sum amounts to Rs. 64800 in 4 years and Rs. 93312 in 6 years. What is the compound interest earned in fifth year?