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Question

In this question, three statements are given, followed by two conclusions numbered I and II. Assuming the statements to be true, even if they seem to be at variance with commonly known facts, decide which of the conclusions logically follows/follow from the statements.
Statements:
I. Some digits are alphabets.
II. All alphabets are books.
III. Some books are novels.
Conclusions:
I. All novels are digits.
II. Some digits are books.

This question was previously asked in
SSC Selection Post 2024 Question Paper (26-Jun-2024) (Shift-4)
The correct answer is
Only conclusion II follows

Analyzing Syllogism Statements

This problem involves logical reasoning, specifically analyzing given statements to determine which conclusions can be logically inferred. We need to assume the three provided statements are true and evaluate the two conclusions.

Statement Breakdown

  • Statement I: Some digits are alphabets. This indicates a non-empty intersection between the set of Digits (D) and the set of Alphabets (A). We can represent this as: $D \cap A \neq \emptyset$.
  • Statement II: All alphabets are books. This means the set of Alphabets (A) is entirely contained within the set of Books (B). This is a subset relationship: $A \subseteq B$.
  • Statement III: Some books are novels. This indicates a non-empty intersection between the set of Books (B) and the set of Novels (N): $B \cap N \neq \emptyset$.

Logical Deduction Steps

We combine the information from the statements to deduce new relationships.

Combining Statement I and Statement II:

  • From Statement I, we know there exists at least one element 'x' such that 'x' is a Digit and 'x' is an Alphabet ($ \exists x (Digit(x) \land Alphabet(x)) $).
  • From Statement II, we know that if 'x' is an Alphabet, then 'x' must also be a Book ($ \forall x (Alphabet(x) \implies Book(x)) $).
  • Therefore, any element 'x' that is both a Digit and an Alphabet must also be a Book. This directly implies that there exists at least one element 'x' which is a Digit and also a Book ($ \exists x (Digit(x) \land Book(x)) $).
  • This confirms the conclusion: Some digits are books. In set notation: Since $D \cap A \neq \emptyset$ and $A \subseteq B$, it must be true that $D \cap B \neq \emptyset$.

Evaluating Conclusion I: All novels are digits

Conclusion I states: All novels are digits ($N \subseteq D$).

  • Statement III tells us $B \cap N \neq \emptyset$ (Some books are novels).
  • We also know $D \cap B \neq \emptyset$ (Some digits are books).
  • However, there is no information linking the set of Novels (N) directly or indirectly to being entirely within the set of Digits (D). The books that are novels might exist completely outside the set of digits.
  • Consider a scenario: Let Digits (D) = {1, 2}, Alphabets (A) = {1}, Books (B) = {1, 3}, Novels (N) = {3, 4}.
    • Statement I holds: $D \cap A = \{1\} \neq \emptyset$ (1 is a digit and an alphabet).
    • Statement II holds: $A = \{1\} \subseteq \{1, 3\} = B$ (All alphabets are books).
    • Statement III holds: $B \cap N = \{3\} \neq \emptyset$ (3 is a book and a novel).
    • Conclusion I check: Is $N = \{3, 4\} \subseteq D = \{1, 2\}$? No, 3 and 4 are not digits.
  • Therefore, Conclusion I does not logically follow from the given statements.

Evaluating Conclusion II: Some digits are books

Conclusion II states: Some digits are books ($D \cap B \neq \emptyset$).

  • As demonstrated in the "Logical Deduction Steps", the combination of Statement I ($D \cap A \neq \emptyset$) and Statement II ($A \subseteq B$) directly leads to the conclusion $D \cap B \neq \emptyset$.
  • The digits that are alphabets (which we know exist from Statement I) must also be books (because of Statement II). Hence, some digits are necessarily books.
  • Therefore, Conclusion II logically follows from the given statements.

Final Summary

Based on the logical analysis of the provided statements:

  • Conclusion I ("All novels are digits") is not a valid inference.
  • Conclusion II ("Some digits are books") is a valid inference.

Thus, only Conclusion II logically follows from the premises.

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