This solution demonstrates how to find the value of $\cos A$ in Triangle ABC given the lengths of its sides: $a = 25$, $b = 45$, and $c = 30$.
To find the cosine of angle A when all three side lengths are known, we use the Law of Cosines:
$ \cos A = \frac{b^2 + c^2 - a^2}{2bc} $
Substitute the provided side lengths into the formula:
$ \cos A = \frac{45^2 + 30^2 - 25^2}{2 \times 45 \times 30} $
The value of $\cos A$ for Triangle ABC is $\frac{23}{27}$.
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