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Question

In the triangle ABC, a = 25, b = 45 and c = 30. The value of $\cos A$ is:

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$\frac{23}{27}$

Triangle Cosine Value Calculation using Law of Cosines

This solution demonstrates how to find the value of $\cos A$ in Triangle ABC given the lengths of its sides: $a = 25$, $b = 45$, and $c = 30$.

Applying the Law of Cosines

To find the cosine of angle A when all three side lengths are known, we use the Law of Cosines:

$ \cos A = \frac{b^2 + c^2 - a^2}{2bc} $

Substituting Given Values

Substitute the provided side lengths into the formula:

  • $a = 25$
  • $b = 45$
  • $c = 30$

$ \cos A = \frac{45^2 + 30^2 - 25^2}{2 \times 45 \times 30} $

Calculation Steps

  1. Calculate the square of each side length:
    • $45^2 = 2025$
    • $30^2 = 900$
    • $25^2 = 625$
  2. Calculate the numerator of the fraction: $2025 + 900 - 625 = 2300$.
  3. Calculate the denominator of the fraction: $2 \times 45 \times 30 = 2700$.
  4. Form the fraction for $\cos A$: $\cos A = \frac{2300}{2700}$.
  5. Simplify the fraction by dividing both the numerator and denominator by 100: $ \cos A = \frac{23}{27} $

Conclusion

The value of $\cos A$ for Triangle ABC is $\frac{23}{27}$.

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