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Question

In the following question below are given some statements followed by some conclusions based on those statements. Taking the given statements to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusion logically follows the given statements.

Statements:

I. No A is B.

II. No C is B.

Conclusion:

I. Some C are not A.

II. Some A are B.

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is Neither conclusion follows

Analyzing Syllogism Statements and Conclusions

This question requires us to analyze the logical relationship between two statements and two conclusions. We must assume the given statements are true, even if they contradict common knowledge, and determine which conclusions logically follow.

Understanding the Given Statements

Let's break down the provided statements:

  1. Statement I: No A is B.
    • This statement tells us that there is absolutely no overlap between the set of A and the set of B. They are completely separate or disjoint.
    • In terms of relationships, if something belongs to A, it cannot belong to B, and vice versa.
  2. Statement II: No C is B.
    • This statement tells us that there is absolutely no overlap between the set of C and the set of B. They are also completely separate or disjoint.
    • If something belongs to C, it cannot belong to B, and vice versa.

Both statements establish a relationship of mutual exclusion with the set B, but they do not directly tell us anything about the relationship between A and C.

Evaluating the Conclusions

A conclusion logically follows from the statements only if it is true in *every possible scenario* where the statements are true. If we can find even one scenario where the statements are true but the conclusion is false, then the conclusion does not logically follow.

Conclusion I: Some C are not A.

This conclusion claims that there are some elements in C that do not belong to A. Let's consider the relationship between A and C based on the given statements:

We know A is disjoint from B ($\text{A} \cap \text{B} = \emptyset$), and C is disjoint from B ($\text{C} \cap \text{B} = \emptyset$). These statements restrict A and C only in relation to B. They don't put any constraints on the relationship between A and C.

Let's visualize possible relationships between A and C (while keeping A and C disjoint from B):

  • Scenario 1: A and C are completely separate (disjoint).
    • If No A is C, then it is true that Some C are not A (in fact, all C are not A, and 'all' implies 'some'). In this scenario, the conclusion is true.
  • Scenario 2: A and C overlap.
    • If Some A are C and Some C are A, then there are parts of C that are not in A. In this scenario, the conclusion "Some C are not A" is true.
  • Scenario 3: C is a subset of A.
    • If All C are A, then every element of C is also an element of A. In this scenario, there are no elements in C that are not in A. The conclusion "Some C are not A" is false.
  • Scenario 4: A is a subset of C.
    • If All A are C, then there are elements in C that are not in A (unless C is empty, which is usually not assumed in syllogisms unless explicitly stated or implied). In this scenario, the conclusion is true.

Since we found a scenario (Scenario 3, where C is a subset of A) where the statements are true but Conclusion I ("Some C are not A") is false, Conclusion I does not logically follow from the statements.

Conclusion II: Some A are B.

This conclusion claims that there is at least one element that belongs to both A and B.

Look back at Statement I: "No A is B". This statement explicitly says that there are *no* elements in common between A and B. Conclusion II ("Some A are B") is the direct contradiction (or rather, the existential affirmation contradicting the universal negation) of Statement I.

If Statement I is true (which we must assume), then Conclusion II must be false. Therefore, Conclusion II does not logically follow from the statements.

Final Decision

Based on our analysis, neither Conclusion I nor Conclusion II logically follows from the given statements because:

  • Conclusion I is not necessarily true in all possible scenarios where the statements hold.
  • Conclusion II directly contradicts Statement I.

Therefore, neither conclusion follows.

Revision Table: Syllogism Analysis Summary

Statement/Conclusion Description Follows? Reasoning
Statement I No A is B ($\text{A} \cap \text{B} = \emptyset$) Given Assumed true as per question instructions.
Statement II No C is B ($\text{C} \cap \text{B} = \emptyset$) Given Assumed true as per question instructions.
Conclusion I Some C are not A ($\exists \text{x} : \text{x} \in \text{C} \land \text{x} \notin \text{A}$) No Can be false if C is a subset of A. The statements provide no direct link between A and C.
Conclusion II Some A are B ($\exists \text{x} : \text{x} \in \text{A} \land \text{x} \in \text{B}$) No Directly contradicts Statement I ("No A is B").

Additional Information on Logical Syllogisms

Syllogisms are a type of logical argument that applies deductive reasoning to arrive at a conclusion based on two or more propositions that are asserted or assumed to be true. Here are some key concepts related to this problem:

  • Statements (Premises): These are the propositions given as true. In this case, "No A is B" and "No C is B".
  • Conclusions: These are propositions that are supposed to follow logically from the statements.
  • Logical Consequence: A conclusion follows logically from statements if and only if it is impossible for the statements to be true and the conclusion false simultaneously. If there's even one possibility where statements are true but the conclusion is false, the conclusion does not follow.
  • Disjoint Sets: The statement "No X is Y" means the sets X and Y have no members in common. Their intersection is empty ($\text{X} \cap \text{Y} = \emptyset$). Both statements in this problem describe disjoint relationships with the set B.
  • Relationship between Universal Negation and Existential Affirmation:
    • "No A is B" is a universal negation (applies to all A and all B regarding their intersection).
    • "Some A are B" is an existential affirmation (claims existence of at least one element in the intersection).
    • These two statements are contradictory. If one is true, the other must be false.
  • Undefined Relationships: If statements do not provide a direct link between two terms (like A and C in this case), then conclusions involving only those two terms usually do not follow unless they are derivable through an intermediate term (which isn't the case here in a way that necessitates the conclusion).

Understanding these principles is crucial for solving syllogism problems correctly. We must rely only on the information given in the statements and the rules of logic.

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Important Questions from Syllogism

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    I. Some Strong are Sharp.

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    I. Some weaks are iron.

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    III. Some women are female.

  4. The statements below are followed by two conclusions labeled I and II. Assuming that the information in the statements is true, even if it appears to be at variance with generally established facts, decide which conclusion(s) logically and definitely follow(s) from the information given in the statements.Statements:

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    Some toys are dolls.

    Conclusions:

    I. Some rings are bangles.

    II. Some dolls are rings.
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