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Question

In each of the following questions, a word is transformed into another word by applying a specific alphabetical pattern to each of its letters. Identify the logic used in the first pair and apply the same logic to the second word to determine the correct answer.
LIGHT : MJGHW :: HEAVY:?

This question was previously asked in
SSC Stenographer 2025 Question Paper (06-Aug-2025) Shift 2
The correct answer is
FAVB

Understanding the Alphabetical Pattern Logic

This question requires us to identify the specific rule or pattern used to change one word into another and then apply that same rule to a different word.

Analyzing the First Word Pair: LIGHT to MJGHW

We first examine the relationship between LIGHT and MJGHW by looking at the shift in alphabetical position for each corresponding letter. We assign numerical values to letters (A=1, B=2, ..., Z=26).

  • The first letter L (12th letter) changes to M (13th letter). This is a shift of \(+1\). The calculation is \(12 + 1 = 13\).
  • The second letter I (9th letter) changes to J (10th letter). This is also a shift of \(+1\). The calculation is \(9 + 1 = 10\).
  • The third letter G (7th letter) remains G (7th letter). This is a shift of \(+0\). The calculation is \(7 + 0 = 7\).
  • The fourth letter H (8th letter) remains H (8th letter). This is a shift of \(+0\). The calculation is \(8 + 0 = 8\).
  • The fifth letter T (20th letter) changes to W (23rd letter). This is a shift of \(+3\). The calculation is \(20 + 3 = 23\).

By analyzing these changes, we identify a sequential pattern of shifts applied to the letters based on their position in the word: \(+1, +1, +0, +0, +3\).

Applying the Pattern to the Second Word: HEAVY

Next, we apply this exact sequence of shifts (\(+1, +1, +0, +0, +3\)) to the letters of the word HEAVY.

  • For the first letter H (8th position): Apply a \(+1\) shift. \(8 + 1 = 9\). The 9th letter is I.
  • For the second letter E (5th position): Apply a \(+1\) shift. \(5 + 1 = 6\). The 6th letter is F.
  • For the third letter A (1st position): Apply a \(+0\) shift. \(1 + 0 = 1\). The 1st letter is A.
  • For the fourth letter V (22nd position): Apply a \(+0\) shift. \(22 + 0 = 22\). The 22nd letter is V.
  • For the fifth letter Y (25th position): Apply a \(+3\) shift. \(25 + 3 = 28\). Since the alphabet has 26 letters, we find the equivalent letter by using modulo arithmetic: \(28 \pmod{26} = 2\). The 2nd letter is B.

Therefore, applying the identified pattern to HEAVY results in the word IFAB.

Conclusion on the Pattern

The logical application of the derived pattern (\(+1, +1, +0, +0, +3\)) to the word HEAVY yields IFAB. It is noted that the provided options include FAVB, HISAT, JENZQ, and GPIDB, with FAVB indicated as the correct answer. The result IFAB differs from the provided correct answer FAVB, suggesting a potential discrepancy in the question details or the given options/answer.

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