If x + y + 3 = 0, then find the value of x 3+ y 3- 9xy + 9.
-18
The problem asks us to find the value of the expression \(x^3 + y^3 - 9xy + 9\), given the condition that \(x + y + 3 = 0\). This problem can be solved by recognizing and applying a useful algebraic identity related to the sum of cubes.
The condition is \(x + y + 3 = 0\). This can be rearranged to \(x + y = -3\).
We know a powerful algebraic identity: For any numbers \(a\), \(b\), and \(c\),
\(a^3 + b^3 + c^3 - 3abc = (a+b+c)(a^2 + b^2 + c^2 - ab - bc - ca)\).
A special case of this identity occurs when \(a + b + c = 0\). In this case, the right side of the identity becomes \((0)(a^2 + b^2 + c^2 - ab - bc - ca) = 0\).
So, if \(a + b + c = 0\), then \(a^3 + b^3 + c^3 - 3abc = 0\), which means \(a^3 + b^3 + c^3 = 3abc\).
Let's compare the given condition \(x + y + 3 = 0\) with the condition \(a + b + c = 0\). We can see a direct correspondence if we let:
With these substitutions, the condition \(a + b + c = 0\) becomes \(x + y + 3 = 0\), which exactly matches the condition given in the problem.
Since \(x + y + 3 = 0\), we can use the identity \(a^3 + b^3 + c^3 = 3abc\) with \(a=x\), \(b=y\), and \(c=3\). Substituting these values into the identity, we get:
\(x^3 + y^3 + 3^3 = 3(x)(y)(3)\)
\(x^3 + y^3 + 27 = 9xy\)
We can rearrange this equation to match parts of the expression we need to evaluate (\(x^3 + y^3 - 9xy + 9\)):
\(x^3 + y^3 - 9xy + 27 = 0\)
From this, we can isolate the \(x^3 + y^3 - 9xy\) part:
\(x^3 + y^3 - 9xy = -27\)
Now we need to find the value of \(x^3 + y^3 - 9xy + 9\). We can substitute the value we just found for \(x^3 + y^3 - 9xy\):
\((x^3 + y^3 - 9xy) + 9\)
\((-27) + 9\)
\(-18\)
The value of the expression \(x^3 + y^3 - 9xy + 9\), given that \(x + y + 3 = 0\), is \(-18\).
| Step | Description | Calculation/Result |
|---|---|---|
| 1 | Given Condition | \(x + y + 3 = 0\) |
| 2 | Relevant Identity (if a+b+c=0) | \(a^3 + b^3 + c^3 = 3abc\) |
| 3 | Map variables | \(a=x, b=y, c=3\) |
| 4 | Apply identity | \(x^3 + y^3 + 3^3 = 3(x)(y)(3)\) |
| 5 | Simplify identity result | \(x^3 + y^3 + 27 = 9xy\) |
| 6 | Rearrange for \(x^3 + y^3 - 9xy\) | \(x^3 + y^3 - 9xy = -27\) |
| 7 | Evaluate target expression | \((x^3 + y^3 - 9xy) + 9 = (-27) + 9\) |
| 8 | Final Value | \(-18\) |
Understanding algebraic identities is crucial for simplifying expressions and solving equations in algebra. Here are a few common and important identities:
| Identity Name | Identity | Notes |
|---|---|---|
| Sum of Cubes | \(a^3 + b^3 = (a+b)(a^2 - ab + b^2)\) | For factoring sum of cubes. |
| Difference of Cubes | \(a^3 - b^3 = (a-b)(a^2 + ab + b^2)\) | For factoring difference of cubes. |
| Cube of a Sum | \((a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3\) | Expanding \((a+b)^3\). |
| Cube of a Difference | \((a-b)^3 = a^3 - 3a^2b + 3ab^2 - b^3\) | Expanding \((a-b)^3\). |
| Sum/Difference of Cubes (General) | \(a^3 + b^3 + c^3 - 3abc = (a+b+c)(a^2 + b^2 + c^2 - ab - bc - ca)\) | Key identity used in this problem. |
| Special Case: \(a+b+c=0\) | If \(a+b+c=0\), then \(a^3 + b^3 + c^3 = 3abc\) | Derived from the general identity. |
Algebraic identities are equations that are true for all possible values of the variables involved. They are powerful tools in algebra because they:
Recognizing patterns in algebraic expressions and matching them to known identities is a key skill in mathematics. The identity \(a^3 + b^3 + c^3 = 3abc\) when \(a+b+c=0\) is a classic example frequently used in problems involving the sum of cubes under a linear constraint.
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