For what value of m will the system of equations 17x + my + 102 = 0 and 23x + 299y + 138 = 0 have infinite number of solutions ?
221
The given system of linear equations is:
We need to find the value of 'm' for which this system has an infinite number of solutions. A system of two linear equations in two variables, say $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$, has infinitely many solutions if the ratio of their corresponding coefficients is equal. That is, the following condition must be satisfied:
$\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$
Let's identify the coefficients from our given equations:
Now, let's set up the ratios of these coefficients:
$\frac{17}{23} = \frac{m}{299} = \frac{102}{138}$
For the system to have infinite solutions, all three ratios must be equal. Let's first simplify the ratio of the constant terms, $\frac{102}{138}$.
We can divide both the numerator and the denominator by their greatest common divisor. Both are even numbers, so we can start by dividing by 2:
$\frac{102 \div 2}{138 \div 2} = \frac{51}{69}$
Now, let's look at 51 and 69. Both are divisible by 3:
$\frac{51 \div 3}{69 \div 3} = \frac{17}{23}$
So, the simplified ratio of constant terms is $\frac{17}{23}$. This matches the ratio of the coefficients of 'x'.
Now, we use the condition $\frac{b_1}{b_2} = \frac{c_1}{c_2}$ (or $\frac{b_1}{b_2} = \frac{a_1}{a_2}$, since all ratios are equal) to find the value of 'm'.
$\frac{m}{299} = \frac{17}{23}$
To solve for 'm', multiply both sides of the equation by 299:
$m = \frac{17}{23} \times 299$
We can simplify this calculation by dividing 299 by 23 before multiplying by 17. Let's perform the division:
$\frac{299}{23} = 13$
So, the equation becomes:
$m = 17 \times 13$
Now, we calculate the product of 17 and 13:
$17 \times 13 = 17 \times (10 + 3) = 17 \times 10 + 17 \times 3 = 170 + 51 = 221$
Thus, the value of 'm' is 221.
Let's verify the ratios with $m = 221$:
| Ratio | Value | Simplified Value |
|---|---|---|
| $\frac{a_1}{a_2}$ | $\frac{17}{23}$ | $\frac{17}{23}$ |
| $\frac{b_1}{b_2}$ | $\frac{m}{299} = \frac{221}{299}$ | Since $221 = 17 \times 13$ and $299 = 23 \times 13$, $\frac{221}{299} = \frac{17 \times 13}{23 \times 13} = \frac{17}{23}$ |
| $\frac{c_1}{c_2}$ | $\frac{102}{138}$ | As calculated earlier, $\frac{102}{138} = \frac{17}{23}$ |
Since $\frac{17}{23} = \frac{221}{299} = \frac{102}{138} = \frac{17}{23}$, the condition for infinite solutions is satisfied when $m = 221$.
Therefore, the value of m for which the given system of equations has an infinite number of solutions is 221.
| Condition on Coefficients ($a_1x+b_1y+c_1=0$, $a_2x+b_2y+c_2=0$) | Number of Solutions | Graphical Representation |
|---|---|---|
| $\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$ | Exactly one solution (Unique Solution) | Intersecting Lines |
| $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$ | Infinitely many solutions | Coincident Lines (One line lies on top of the other) |
| $\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}$ | No solution | Parallel Lines (Non-intersecting) |
A system of linear equations is a set of two or more linear equations involving the same variables. In this case, we have a system of two linear equations in two variables, 'x' and 'y'.
Solving a system of linear equations means finding the values of the variables that satisfy all equations in the system simultaneously. The solution can be found using various methods:
The type of solution (unique, infinite, or no solution) depends on the relationship between the lines represented by the equations, which is determined by the ratios of their coefficients.
What is the solution of the following equations ?
2x + 3y = 12 and 3x − 2y = 5
Two positive numbers differ by 1280. When the greater number is divided by the smaller number, the quotient is 7 and the remainder is 50. The greater number is:
When 5 children from class A join class B, the number of children in both classes is the same. If 25 children from B, join A, then the number of children in A becomes double the number of children in B. The ratio of the number of children in A to those in B is:
If (x + 6y) = 8, and xy = 2, where x > 0, what is the value of (x 3+ 216y 3)?
If 8k 6+ 15k 3– 2 = 0, then the positive value of \(\left( {{\rm{k}}\,{\rm{ + }}\,\frac{1}{{\rm{k}}}} \right)\) is :