The following table shows the average speed (in km per hour) of five different trains A-E during six days of a week from Monday through Saturday. Some data is missing in the table ( indicated as '-') that you are expected to calculate, if required. Based on the data in the table, answer the question that follows: Train - wise speed (in km/hour) on different DaysTrain Average Speed (in km/hr) of Trains Monday Tuesday Wednesday Thursday Friday Saturday A 72 80 - 64 54 - B 88 - 80 84 72 90 C 54 70 72 - 64 60 D - 120 95 - 90 110 E 72 80 84 75 - -
If train B covers a total distance of 3400 km during all the six days by taking a total time of 40 hours, then the average speed of this train during all the six days together is ____% less than the average speed of this train on Monday. (Rounded-off to two digits after decimal)
3.41
To solve this problem, we need to find the average speed of Train B over all six days and compare it with the speed on Monday.
- First, calculate the average speed of Train B over the six days:
- Total distance covered by Train B in six days = 3400 km.
- Total time taken by Train B in six days = 40 hours.
- Average speed over the six days = Total Distance / Total Time.
- \(\text{Average Speed} = \frac{3400}{40} = 85 \text{ km/hr}\)
- Next, note the speed of Train B on Monday from the given table:
- Average speed of Train B on Monday = 88 km/hr.
- Calculate the percentage difference between the two speeds:
- Difference in speed = 88 - 85 = 3 km/hr.
- Percentage difference = \(\left(\frac{\text{Difference}}{\text{Speed on Monday}}\right) \times 100\)
- Percentage difference = \(\left(\frac{3}{88}\right) \times 100 \approx 3.41\%\)
- Therefore, the average speed of Train B during all six days together is approximately 3.41% less than the average speed of this train on Monday.
Thus, the correct answer is 3.41% less.
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