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Question

If the radius of the base of a right circular cylinder is decreased by 19% and its height is increased by 129%, then what is the percentage increase in its volume? [Give your answer correct to the nearest integer value.]

This question was previously asked in
RRB ALP 2025 CBT 2 Mechanic Motor Vehicle Question Paper (28-Jul-2026) (Shift 1)
The correct answer is
50%

Cylinder Volume Percentage Change Calculation

We need to find the percentage increase in the volume of a right circular cylinder when its radius decreases by 19% and its height increases by 129%.

Volume Formula and Initial Values

The volume (\(V\)) of a right circular cylinder is given by the formula:

\( V = \pi r^2 h \)

Let the initial radius be \(r_1\) and the initial height be \(h_1\). The initial volume is:

\( V_1 = \pi r_1^2 h_1 \)

Calculating New Dimensions

The radius is decreased by 19%. The new radius (\(r_2\)) is:

\( r_2 = r_1 - (0.19 \times r_1) = r_1 (1 - 0.19) = 0.81 r_1 \)

The height is increased by 129%. The new height (\(h_2\)) is:

\( h_2 = h_1 + (1.29 \times h_1) = h_1 (1 + 1.29) = 2.29 h_1 \)

Calculating New Volume

The new volume (\(V_2\)) using the new dimensions is:

\( V_2 = \pi r_2^2 h_2 \)

Substitute the expressions for \(r_2\) and \(h_2\):

\( V_2 = \pi (0.81 r_1)^2 (2.29 h_1) \)

\( V_2 = \pi (0.81^2 r_1^2) (2.29 h_1) \)

\( V_2 = \pi (0.6561 r_1^2) (2.29 h_1) \)

\( V_2 = (0.6561 \times 2.29) (\pi r_1^2 h_1) \)

Calculate the product \(0.6561 \times 2.29\):

\( 0.6561 \times 2.29 \approx 1.502469 \)

So, the new volume is approximately:

\( V_2 \approx 1.502469 V_1 \)

Determining Percentage Increase

The percentage increase in volume is calculated as:

\( \text{Percentage Increase} = \frac{V_2 - V_1}{V_1} \times 100 \% \)

\( \text{Percentage Increase} = \frac{1.502469 V_1 - V_1}{V_1} \times 100 \% \)

\( \text{Percentage Increase} = \frac{(1.502469 - 1) V_1}{V_1} \times 100 \% \)

\( \text{Percentage Increase} = 0.502469 \times 100 \% \)

\( \text{Percentage Increase} \approx 50.2469 \% \)

Rounding to the nearest integer value, the percentage increase is 50%.

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  3. The sides of a triangular park are 60 m, 297 m and 303 m. Its area is equal to the area of a square-shaped garden. What is the perimeter (in m) of the garden?

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