The problem asks us to find the final radius of a sphere after it has been enlarged. We know that the enlargement caused the radius to increase by 2 cm, and this resulted in the surface area increasing by a specific amount, 704 cm\(^2\). We are also given the value of pi to use in our calculations: \(\pi = \frac{22}{7}\).
Let's denote the original radius of the sphere as '\(r\)' cm. According to the problem, the radius is increased by 2 cm. So, the new radius will be '\(r + 2\)' cm.
The formula for the surface area '\(A\)' of a sphere with radius '\(R\)' is given by:
\(A = 4 \pi R^2\)In our case, we have two scenarios:
The problem states that the surface area increases by 704 cm\(^2\). This means:
\(A_{new} - A_{old} = 704\)Substituting the formulas:
\(4 \pi (r+2)^2 - 4 \pi r^2 = 704\)Let's solve the equation step-by-step:
The calculation shows that the original radius was 13 cm. After increasing the radius by 2 cm, the new radius becomes 15 cm. This matches one of the options provided.
The sides of the rectangle are in the ratio 8 : 10 and its perimeter is 90 cm. The area of this rectangle is:
Find the number of bricks, each measuring 24 cm × 12 cm × 8 cm, required to construct a wall 24 m long, 8 m high, and 60 cm thick if 10% of the wall is filled with mortar?
If the sum of lengths of two adjacent sides of a parallelogram is 12 cm, then the perimeter of the parallelogram is:
From a rectangular cardboard sheet of length 46 m and breadth 8 m, three circular plates of radii 3 m, 2 m and 1 m are cut out. If the area of the remaining part of the cardboard sheet is equal to the area of a square, then find the length of each side of the square (use π = 22/7).
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