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Question

If the radius of a sphere is increased by 2 cm, then its surface area increases by 704 cm\(^2\). Using \(\pi = \frac{22}{7}\), find the radius of the sphere after the increase.

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is
15 cm

Understanding the Sphere Surface Area Problem

The problem asks us to find the final radius of a sphere after it has been enlarged. We know that the enlargement caused the radius to increase by 2 cm, and this resulted in the surface area increasing by a specific amount, 704 cm\(^2\). We are also given the value of pi to use in our calculations: \(\pi = \frac{22}{7}\).

Let's denote the original radius of the sphere as '\(r\)' cm. According to the problem, the radius is increased by 2 cm. So, the new radius will be '\(r + 2\)' cm.

Surface Area Formula and Equation Setup

The formula for the surface area '\(A\)' of a sphere with radius '\(R\)' is given by:

\(A = 4 \pi R^2\)

In our case, we have two scenarios:

  • Original Surface Area (\(A_{old}\)) with radius '\(r\)': \(A_{old} = 4 \pi r^2\)
  • New Surface Area (\(A_{new}\)) with radius '\(r+2\)': \(A_{new} = 4 \pi (r+2)^2\)

The problem states that the surface area increases by 704 cm\(^2\). This means:

\(A_{new} - A_{old} = 704\)

Substituting the formulas:

\(4 \pi (r+2)^2 - 4 \pi r^2 = 704\)

Step-by-Step Calculation

Let's solve the equation step-by-step:

  1. Factor out common terms: \(4 \pi [(r+2)^2 - r^2] = 704\)
  2. Substitute the value of \(\pi\): \(4 \times \frac{22}{7} [(r+2)^2 - r^2] = 704\) \(\frac{88}{7} [(r+2)^2 - r^2] = 704\)
  3. Expand the squared term \((r+2)^2\): \((r+2)^2 = r^2 + 2(r)(2) + 2^2 = r^2 + 4r + 4\). \(\frac{88}{7} [ (r^2 + 4r + 4) - r^2 ] = 704\)
  4. Simplify the expression inside the brackets: The '\(r^2\)' terms cancel out. \(\frac{88}{7} [ 4r + 4 ] = 704\)
  5. Isolate the term with '\(r\)': Multiply both sides by \(\frac{7}{88}\) to isolate '\(4r + 4\)'. \(4r + 4 = 704 \times \frac{7}{88}\) Since \(704 \div 88 = 8\), \(4r + 4 = 8 \times 7\) \(4r + 4 = 56\)
  6. Solve for the original radius '\(r\)': Subtract 4 from both sides. \(4r = 56 - 4\) \(4r = 52\) Divide by 4: \(r = \frac{52}{4}\) \(r = 13 \text{ cm}\) This is the original radius.
  7. Find the new radius: The question asks for the radius *after* the increase. New Radius = Original Radius + 2 cm New Radius = \(r + 2\) New Radius = \(13 + 2\) New Radius = \(15 \text{ cm}\)

Final Answer Determination

The calculation shows that the original radius was 13 cm. After increasing the radius by 2 cm, the new radius becomes 15 cm. This matches one of the options provided.

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Similar Questions

  1. The volume of a wall that is 5 times as high as it is broad and 8 times as long as it is high is 12.8 cubic meters. Find the breadth of the wall.
  2. The volume of a solid cylinder is 5,236 cm$^3$ and its height is 34 cm. What is the total surface area of the solid cylinder? $\left(\text{Use } \pi = \frac{22}{7}\right)$
  3. Find the area of a regular hexagon whose side measures \(18\sqrt{2}\) cm. (Use \(\sqrt{3} = 1.73\))
  4. The sides of the rectangle are in the ratio 8 : 10 and its perimeter is 90 cm. The area of this rectangle is:

  5. Find the number of bricks, each measuring 24 cm × 12 cm × 8 cm, required to construct a wall 24 m long, 8 m high, and 60 cm thick if 10% of the wall is filled with mortar?

  6. If the sum of lengths of two adjacent sides of a parallelogram is 12 cm, then the perimeter of the parallelogram is:

  7. From a rectangular cardboard sheet of length 46 m and breadth 8 m, three circular plates of radii 3 m, 2 m and 1 m are cut out. If the area of the remaining part of the cardboard sheet is equal to the area of a square, then find the length of each side of the square (use π = 22/7).

  8. In a workshop calculation, you need to find the side of a square base with an area of 64 cm2. What is the correct length?

  9. Calculate the area of an irregular plot using the Trapezoidal Rule, given the offsets are 2 m, 4 m, 3 m, and 5 m at an equal spacing of 1 m.

  10. In figure 'o' is the centre of a circle. The area of sector OAPB is $\frac{5}{18}$ of the area of the circle find $x$.


Important Questions from Mensuration

  1. The volume of a wall that is 5 times as high as it is broad and 8 times as long as it is high is 12.8 cubic meters. Find the breadth of the wall.
  2. What is the perimeter of an equilateral triangle with side 13 cm?
  3. The perimeter of a square is 76 m. Its area (in $m^2$) is:
  4. A cylindrical rod has an outer curved surface area of 1800 cm$^2$. If the length of the rod is 52 cm, then the outer radius (in cm) of the rod, correct to two places of decimal, is:
    Take $\pi = \frac{22}{7}$
  5. A spherical tank has a diameter of 10 metres. What is the volume of the spherical tank? (Use $\pi = 3.141$)

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