This problem asks us to find the area of a square when we know its perimeter. Let's break down how to solve this step-by-step.
A square is a special shape with four equal sides. The perimeter is the total distance around the outside of the square. The area is the space enclosed within the square.
We are given that the perimeter of the square is 76 meters. The formula for the perimeter ($P$) of a square with side length ($s$) is:
$P = 4s$
To find the length of one side ($s$), we can rearrange the formula:
$s = \frac{P}{4}$
Now, we substitute the given perimeter value:
$s = \frac{76 \text{ m}}{4}$
Calculating this gives us:
$s = 19 \text{ m}$
So, each side of the square is 19 meters long.
The formula for the area ($A$) of a square is the side length multiplied by itself:
$A = s \times s = s^2$
Using the side length we just found ($s = 19$ m):
$A = (19 \text{ m})^2$
$A = 19 \times 19 \text{ m}^2$
Calculating the square of 19:
$A = 361 \text{ m}^2$
Therefore, the area of the square is 361 square meters.
The area of the square is 361 $m^2$. This matches option 3.
A spherical tank has a diameter of 10 metres. What is the volume of the spherical tank? (Use $\pi = 3.141$)