The following table shows the average speed (in km per hour) of five different trains A-E during six days of a week from Monday through Saturday. Some data is missing in the table ( indicated as '-') that you are expected to calculate, if required. Based on the data in the table, answer the question that follows: Train - wise speed (in km/hour) on different DaysTrain Average Speed (in km/hr) of Trains Monday Tuesday Wednesday Thursday Friday Saturday A 72 80 - 64 54 - B 88 - 80 84 72 90 C 54 70 72 - 64 60 D - 120 95 - 90 110 E 72 80 84 75 - -
If the mean of the average speeds of train C during all the six days is 25% less than the average speed of train B on Saturday, then the average speed of train D on Tuesday is approximately ___% more than that of train C on Thursday?
41
First find train C's missing Thursday value using the given condition. The mean of C over six days is 25% less than train B's Saturday speed. B's Saturday speed = 90, so 25% less = 90 × 0.75 = 67.5.
Hence C's six-day total = 67.5 × 6 = 405.
C's known days: 54 + 70 + 72 + 64 + 60 = 320.
So C's Thursday = 405 − 320 = 85 km/hour.
From the table, train D's Tuesday speed = 120.
Now compute by how much 120 exceeds 85: (120 − 85) / 85 × 100 = 35 / 85 × 100 = 41.18% ≈ 41%.
Therefore the answer is 41. Values like 35 or 38 would arise from a wrong base or wrong Thursday figure.
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