Given that $\tan\theta = 1$ and $\theta$ is an acute angle.
The angle $\theta$ for which the tangent is 1 is $45^\circ$. So, $\theta = 45^\circ$.
For $\theta = 45^\circ$, we find the required trigonometric values:
The expression is $2 \sin\theta \cos\theta - \text{cosec}^2\theta$. Substitute the calculated values:
$ 2 \sin\theta \cos\theta - \text{cosec}^2\theta = 2 \left( \frac{1}{\sqrt{2}} \right) \left( \frac{1}{\sqrt{2}} \right) - 2 $
Simplify the expression:
$ = 2 \left( \frac{1}{2} \right) - 2 $
$ = 1 - 2 $
$ = -1 $
Thus, the value of the expression is $-1$.
If $\tan\theta = \frac{5}{12}$, $0 < \theta < \frac{\pi}{2}$, then the value of $\frac{\cos\theta + 5\cot\theta}{\text{cosec}\theta - \cos\theta}$ will be:
If cosec θ = 13/12, then sin θ + cos θ - tan θ is equal to:
What is the value of \(\frac{3 \sin 58^{\circ}}{\cos 32^{\circ}}+\frac{3 \sin 42^{\circ}}{\cos 48^{\circ}}\) ?
If \(\frac{{\tan \theta + \sin \theta }}{{\tan \theta - \sin \theta }} = \frac{{k + 1}}{{k - 1}},\) then k = ?
If α + β = 90° and α = 2β, then the value of 3 cos 2 α - 2 sin 2 β is equal to:
If \(\sqrt{3}\) tan θ = 3 sin θ, then what is the value of sin 2θ − cos 2θ ?