We are given the expression $P = \tan\theta + \sec\theta$. Our goal is to find the value of $\tan\theta$ in terms of $P$.
We know the fundamental trigonometric identity: $ \sec^2\theta - \tan^2\theta = 1 $ This can be factored as the difference of squares:
$ (\sec\theta - \tan\theta)(\sec\theta + \tan\theta) = 1 $
Substitute the given expression $P = \tan\theta + \sec\theta$ into the factored identity:
$ (\sec\theta - \tan\theta) P = 1 $
Now, we can express $(\sec\theta - \tan\theta)$ in terms of $P$:
$ \sec\theta - \tan\theta = \frac{1}{P} $
We now have a system of two linear equations involving $\sec\theta$ and $\tan\theta$:
To find $\tan\theta$, subtract the second equation from the first:
$ (\sec\theta + \tan\theta) - (\sec\theta - \tan\theta) = P - \frac{1}{P} $
Simplify the left side:
$ \sec\theta + \tan\theta - \sec\theta + \tan\theta = P - \frac{1}{P} $
$ 2\tan\theta = P - \frac{1}{P} $
Combine the terms on the right side using a common denominator:
$ 2\tan\theta = \frac{P \cdot P}{P} - \frac{1}{P} $
$ 2\tan\theta = \frac{P^2 - 1}{P} $
Finally, divide by 2 to isolate $\tan\theta$:
$ \tan\theta = \frac{P^2 - 1}{2P} $
This matches the value provided in Option D.
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