Given the equation $\cos 2\theta = \frac{1}{2}$.
We know that the principal value for which the cosine is $\frac{1}{2}$ is $60^\circ$.
Therefore, $2\theta = 60^\circ$.
Solving for $\theta$, we get $\theta = \frac{60^\circ}{2} = 30^\circ$.
The expression to evaluate is $\sin(75^\circ - \theta)$.
Substitute the value of $\theta = 30^\circ$ into the expression:
$\sin(75^\circ - 30^\circ) = \sin(45^\circ)$
The value of $\sin(45^\circ)$ is a standard trigonometric value.
$\sin(45^\circ) = \frac{1}{\sqrt{2}}$
Thus, the value of $\sin(75^\circ - \theta)$ is $\frac{1}{\sqrt{2}}$.
What is the ratio of the greatest to the smallest value of 2 – 2 sin x – sin 2x, 0 ≤ x ≤ (π/2)?
If sinθ = \(\frac{4}{5}\) , Find the value of sin3θ
If x, y are acute angles, where 0 < x + y < 90° and sin(3x - 40°) = cos (3y + 40°), then the value of tan (x + y) is equal to
What is (1 + cot θ - cosec θ)(1 + tan θ + sec θ) equal to?
If \(\sin \theta =\frac{3}{5}\) and \(\cos \theta =\frac{4}{5}\) , then the value of \(\frac{1+\tan \theta}{1-\cot \theta}\) is: