We need to find the value of the angle $\theta$ in degrees, given the trigonometric equation $\sin \theta = \cos \theta$.
Start with the given equation:
$ \sin \theta = \cos \theta $
Divide both sides by $\cos \theta$. This is valid as long as $\cos \theta \neq 0$.
$ \frac{\sin \theta}{\cos \theta} = \frac{\cos \theta}{\cos \theta} $
$ \frac{\sin \theta}{\cos \theta} = 1 $
Apply the tangent trigonometric identity, which states that $\tan \theta = \frac{\sin \theta}{\cos \theta}$. The equation simplifies to:
$ \tan \theta = 1 $
Identify the angle $\theta$ in degrees for which the tangent value is 1. This angle is:
$ \theta = 45^{\circ} $
We confirm our assumption: $\cos(45^{\circ}) = \frac{\sqrt{2}}{2}$, which is not zero, validating the division step.
The value of $\theta$ that satisfies $\sin \theta = \cos \theta$ is $45^{\circ}$.
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