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Question

If $cotA = x + \frac{1}{x}$, then what is $cosec^2A$?

This question was previously asked in
SSC CGL 2025 Tier 2 Paper 1 Question Paper (19-Jan-2026)
The correct answer is
$x^2 + \frac{1}{x^2} + 3$

Trigonometric Calculation for $cosec^2A$

The question asks for the value of $cosec^2A$ given the expression for $cotA$. We can solve this using a standard trigonometric identity.

Key Trigonometric Identity

The fundamental relationship between $cotA$ and $cosec^2A$ is given by the identity:

$cosec^2A = 1 + cot^2A$

Step-by-Step Solution

  • We are given $cotA = x + \frac{1}{x}$
  • First, find $cot^2A$ by squaring the given expression for $cotA$:
    $cot^2A = \left(x + \frac{1}{x}\right)^2$
  • Expand the squared term using the formula $(a+b)^2 = a^2 + 2ab + b^2$:
    $cot^2A = x^2 + 2(x)\left(\frac{1}{x}\right) + \left(\frac{1}{x}\right)^2$
    $cot^2A = x^2 + 2 + \frac{1}{x^2}$
  • Now, substitute this value of $cot^2A$ back into the trigonometric identity $cosec^2A = 1 + cot^2A$:
    $cosec^2A = 1 + \left(x^2 + 2 + \frac{1}{x^2}\right)$
  • Simplify the expression:
    $cosec^2A = x^2 + \frac{1}{x^2} + 1 + 2$
    $cosec^2A = x^2 + \frac{1}{x^2} + 3$

Therefore, the value of $cosec^2A$ is $x^2 + \frac{1}{x^2} + 3$. This matches Option 1.

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Important Questions from Trigonometric Ratios and Identities

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