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Question

If $\cos(A) = \frac{7}{25}$, then what is $\text{cosec}(A)$?

This question was previously asked in
SSC CGL 2025 Tier 1 Question Paper (25-Sep-2025) (Shift 3)
The correct answer is
$\frac{25}{24}$

Trigonometry: Calculate Cosecant from Cosine

We are given the value of cosine of an angle A and need to find the value of its cosecant.

Given: $\cos(A) = \frac{7}{25}$

Using Trigonometric Identities

We can use the fundamental Pythagorean identity:

\[ \sin^2(A) + \cos^2(A) = 1 \]

Substitute the given value of $\cos(A)$:

\[ \sin^2(A) + \left(\frac{7}{25}\right)^2 = 1 \]

Calculate the square:

\[ \sin^2(A) + \frac{49}{625} = 1 \]

Isolate $\sin^2(A)$:

\[ \sin^2(A) = 1 - \frac{49}{625} \] \[ \sin^2(A) = \frac{625 - 49}{625} \] \[ \sin^2(A) = \frac{576}{625} \]

Find $\sin(A)$ by taking the square root:

Note: Assuming angle A is in the first quadrant, where sine is positive.

\[ \sin(A) = \sqrt{\frac{576}{625}} = \frac{24}{25} \]

Calculate Cosecant

The definition of cosecant is the reciprocal of sine:

\[ \text{cosec}(A) = \frac{1}{\sin(A)} \]

Substitute the calculated value of $\sin(A)$:

\[ \text{cosec}(A) = \frac{1}{\frac{24}{25}} \] \[ \text{cosec}(A) = \frac{25}{24} \]

Alternative Method: Right-Angled Triangle

Consider a right-angled triangle where angle A is one of the acute angles.

We know $\cos(A) = \frac{\text{Adjacent}}{\text{Hypotenuse}}$. So, let Adjacent = 7 and Hypotenuse = 25.

Using the Pythagorean theorem (Opposite$^2$ + Adjacent$^2$ = Hypotenuse$^2$):

Opposite$^2 + 7^2 = 25^2$

Opposite$^2 + 49 = 625$

Opposite$^2 = 625 - 49 = 576$

Opposite = $\sqrt{576} = 24$

Now, calculate cosecant: $\text{cosec}(A) = \frac{\text{Hypotenuse}}{\text{Opposite}} = \frac{25}{24}$.

Both methods confirm the result.

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