If \({\rm{E}}\left( {\rm{\theta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\theta }}}&{\sin {\rm{\theta }}}\\ { - \sin {\rm{\theta \;}}}&{\cos {\rm{\theta }}} \end{array}} \right]\) then E(α) E(β) is equal to
E(α + β)
We are given a matrix \({\rm{E}}\left( {\rm{\theta }} \right)\) defined as:
\[{\rm{E}}\left( {\rm{\theta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\theta }}}&{\sin {\rm{\theta }}}\\ { - \sin {\rm{\theta \;}}}&{\cos {\rm{\theta }}} \end{array}} \right]\]We need to find the product of \({\rm{E}}\left( {\rm{\alpha }} \right)\) and \({\rm{E}}\left( {\rm{\beta }} \right)\). Based on the definition of \({\rm{E}}\left( {\rm{\theta }} \right)\), we can write \({\rm{E}}\left( {\rm{\alpha }} \right)\) and \({\rm{E}}\left( {\rm{\beta }} \right)\) by replacing \({\rm{\theta }}\) with \({\rm{\alpha }}\) and \({\rm{\beta }}\) respectively.
\[{\rm{E}}\left( {\rm{\alpha }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\alpha }}}&{\sin {\rm{\alpha }}}\\ { - \sin {\rm{\alpha \;}}}&{\cos {\rm{\alpha }}} \end{array}} \right]\] \[{\rm{E}}\left( {\rm{\beta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\beta }}}&{\sin {\rm{\beta }}}\\ { - \sin {\rm{\beta \;}}}&{\cos {\rm{\beta }}} \end{array}} \right]\]Now, let's multiply \({\rm{E}}\left( {\rm{\alpha }} \right)\) by \({\rm{E}}\left( {\rm{\beta }} \right)\). To multiply two \(2 \times 2\) matrices, we take the dot product of the rows of the first matrix with the columns of the second matrix.
\[{\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\alpha }}}&{\sin {\rm{\alpha }}}\\ { - \sin {\rm{\alpha \;}}}&{\cos {\rm{\alpha }}} \end{array}} \right] \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\beta }}}&{\sin {\rm{\beta }}}\\ { - \sin {\rm{\beta \;}}}&{\cos {\rm{\beta }}} \end{array}} \right]\]Let the resulting matrix be \({\rm{R}} = {\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right) = \left[ {\begin{array}{*{20}{c}} {{{\rm{r}}_{11}}}&{{{\rm{r}}_{12}}}\\ {{{\rm{r}}_{21}}}&{{{\rm{r}}_{22}}} \end{array}} \right]\). We calculate each element:
| Element | Calculation |
|---|---|
| \({\rm{r}}_{11}\) | \((\cos {\rm{\alpha}})(\cos {\rm{\beta}}) + (\sin {\rm{\alpha}})(-\sin {\rm{\beta}}) = \cos {\rm{\alpha}}\cos {\rm{\beta}} - \sin {\rm{\alpha}}\sin {\rm{\beta}}\) |
| \({\rm{r}}_{12}\) | \((\cos {\rm{\alpha}})(\sin {\rm{\beta}}) + (\sin {\rm{\alpha}})(\cos {\rm{\beta}}) = \cos {\rm{\alpha}}\sin {\rm{\beta}} + \sin {\rm{\alpha}}\cos {\rm{\beta}}\) |
| \({\rm{r}}_{21}\) | \((-\sin {\rm{\alpha}})(\cos {\rm{\beta}}) + (\cos {\rm{\alpha}})(-\sin {\rm{\beta}}) = -\sin {\rm{\alpha}}\cos {\rm{\beta}} - \cos {\rm{\alpha}}\sin {\rm{\beta}}\) |
| \({\rm{r}}_{22}\) | \((-\sin {\rm{\alpha}})(\sin {\rm{\beta}}) + (\cos {\rm{\alpha}})(\cos {\rm{\beta}}) = -\sin {\rm{\alpha}}\sin {\rm{\beta}} + \cos {\rm{\alpha}}\cos {\rm{\beta}}\) |
So, the resulting matrix is:
\[{\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\alpha}}\cos {\rm{\beta}} - \sin {\rm{\alpha}}\sin {\rm{\beta}}}&{\cos {\rm{\alpha}}\sin {\rm{\beta}} + \sin {\rm{\alpha}}\cos {\rm{\beta}}}\\ { -(\sin {\rm{\alpha}}\cos {\rm{\beta}} + \cos {\rm{\alpha}}\sin {\rm{\beta}})}&{\cos {\rm{\alpha}}\cos {\rm{\beta}} - \sin {\rm{\alpha}}\sin {\rm{\beta}}} \end{array}} \right]\]We can simplify the elements of this matrix using the angle addition formulas from trigonometry:
Using these identities with \({\rm{A}} = {\rm{\alpha}}\) and \({\rm{B}} = {\rm{\beta}}\), we can rewrite the matrix elements:
Substituting these back into the matrix, we get:
\[{\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos({\rm{\alpha}} + {\rm{\beta}})}&{\sin({\rm{\alpha}} + {\rm{\beta}})}\\ { - \sin({\rm{\alpha}} + {\rm{\beta}})}&{\cos({\rm{\alpha}} + {\rm{\beta}})} \end{array}} \right]\]Let's compare this resulting matrix with the original definition of \({\rm{E}}\left( {\rm{\theta }} \right)\). If we replace \({\rm{\theta }}\) with \({\rm{\alpha}} + {\rm{\beta}}\) in the expression for \({\rm{E}}\left( {\rm{\theta }} \right)\), we get:
\[{\rm{E}}\left( {\rm{\alpha }} + {\rm{\beta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos ({\rm{\alpha }} + {\rm{\beta }})}&{\sin ({\rm{\alpha }} + {\rm{\beta }})}\\ { - \sin ({\rm{\alpha }} + {\rm{\beta }})}&{\cos ({\rm{\alpha }} + {\rm{\beta }})} \end{array}} \right]\]We can see that the result of \({\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right)\) is exactly the same as \({\rm{E}}\left( {\rm{\alpha }} + {\rm{\beta }} \right)\).
Therefore, \({\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right)\) is equal to \({\rm{E}}\left( {\rm{\alpha }} + {\rm{\beta }} \right)\).
| Concept | Description | Relevance to Problem |
|---|---|---|
| Matrix Multiplication | Process of multiplying two matrices to get a new matrix. The element in the i-th row and j-th column of the product is the dot product of the i-th row of the first matrix and the j-th column of the second matrix. | Used to calculate the product \({\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right)\). |
| Angle Addition Formulas | Trigonometric identities relating the cosine and sine of the sum of two angles (\(\cos({\rm{A}} + {\rm{B}})\), \(\sin({\rm{A}} + {\rm{B}})\)) to the sines and cosines of the individual angles. | Used to simplify the elements of the resulting matrix after multiplication. |
| Rotation Matrix | A matrix of the form \({\rm{E}}\left( {\rm{\theta }} \right)\) represents a 2D rotation by angle \({\rm{\theta }}\) counterclockwise around the origin. | Understanding the geometric interpretation helps see why \({\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right)\) corresponds to a rotation by \({\rm{\alpha}} + {\rm{\beta}}\). |
The matrix \({\rm{E}}\left( {\rm{\theta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\theta }}}&{\sin {\rm{\theta }}}\\ { - \sin {\rm{\theta \;}}}&{\cos {\rm{\theta }}} \end{array}} \right]\) is a standard representation of a 2D rotation matrix. Specifically, it represents a clockwise rotation by angle \({\rm{\theta }}\) about the origin. A counterclockwise rotation matrix is given by \(\left[ {\begin{array}{*{20}{c}} {\cos {\rm{\theta }}}&{ - \sin {\rm{\theta }}}\\ {\sin {\rm{\theta \;}}}&{\cos {\rm{\theta }}} \end{array}} \right]\). The given matrix has \(+\sin {\rm{\theta }}\) in the top right and \(-\sin {\rm{\theta }}\) in the bottom left, which corresponds to a clockwise rotation by \({\rm{\theta }}\). When you apply a rotation by \({\rm{\alpha }}\) followed by a rotation by \({\rm{\beta }}\), the net effect is a rotation by \({\rm{\alpha}} + {\rm{\beta}}\). This geometric property explains why multiplying the matrices \({\rm{E}}\left( {\rm{\alpha }} \right)\) and \({\rm{E}}\left( {\rm{\beta }} \right)\) results in \({\rm{E}}\left( {\rm{\alpha }} + {\rm{\beta }} \right)\). This result is consistent regardless of whether the matrix represents clockwise or counterclockwise rotation, as multiplying rotations corresponds to adding angles.
Consider the following in respect of matrices A, B and C of same order:
1) (A + B + C)' = A' + B’ + C’
2) (AB)’ = A’B’
3) (ABC)’ = C’B’A’
Where A’ is the transpose of the matrix A.
Which of the above are correct?If \({\rm{A}} = \left[ {\begin{array}{*{20}{c}} 1&0&{ - 2}\\ 2&{ - 3}&4 \end{array}} \right]\) , then the matrix X for which 2X + 3A = 0 holds true is
Let \(A = \begin{bmatrix} 0 & 2 \\ -2 & 0 \end{bmatrix}\) and (mI + nA) 2= A where m, n are positive real numbers and I is the identify matrix. What is (m + n) equal to?
Let \({\rm{A}} = \left[ {\begin{array}{*{20}{c}} {\rm x + y}& \rm y\\ {\rm 2x}&{\rm x - y} \end{array}} \right],\;\rm B = \left[ {\begin{array}{*{20}{c}} 2\\ { - 1} \end{array}} \right]\) and \(\rm C = \left[ {\begin{array}{*{20}{c}} 3\\ 2 \end{array}} \right]\) . If AB = C, then what is the value of the determinant of the matrix A?
If \(A = \left[ {\begin{array}{c} 1&{ - 1}\\ { - 1}&1 \end{array}} \right],\) then the expression A 3- 2A 2is
If \(A = \left( {\begin{array}{*{20}{c}} 1&2\\ 2&3\\ 3&4 \end{array}} \right)\) and \(B = \left( {\begin{array}{*{20}{c}} 1&2\\ 2&1 \end{array}} \right),\) then which one of the following is correct?
A square matrix A is called orthogonal if_______ where A’ is the transpose of A.
Consider the following in respect of matrices A and B of same order:
1) A 2– B 2= (A + B) (A – B)
2) (A – I) (I + A) = O ⇔ A 2= I
Where I is the identity matrix and O is the null matrix.
Which of the above is/are correct?If A is a 2 × 3 matrix and AB is a 2 × 5 matrix, then B must be a
If \(A = \left( {\begin{array}{} 1&2\\ 2&3 \end{array}} \right)\) and A 2– kA – I 2= 0, where I 2is the 2 × 2 identity matrix, then what is the value of k?
The adjoint of matrix \(\left[ {\begin{array}{*{20}{c}} a&b\\ c&d \end{array}} \right]\)is
Consider the following in respect of matrices A, B and C of same order:
1) (A + B + C)' = A' + B’ + C’
2) (AB)’ = A’B’
3) (ABC)’ = C’B’A’
Where A’ is the transpose of the matrix A.
Which of the above are correct?If \({\rm{A}} = \left[ {\begin{array}{*{20}{c}} 1&0&{ - 2}\\ 2&{ - 3}&4 \end{array}} \right]\) , then the matrix X for which 2X + 3A = 0 holds true is
Find a matrix X such that 2A + B + X = 0 , where
\(A=\begin{bmatrix} -1 & 2 \\\ 3 & 4 \end{bmatrix} \ \text{and} \;\rm B =\ \begin{bmatrix} 3 & -2 \\\ 1 & 5 \end{bmatrix} \ ?\)
The solution of the matrix equation \(\left[ {\begin{array}{*{20}{c}} 2&{ - 1}&3\\ 1&1&1\\ 1&{ - 1}&1 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} x\\ y\\ z \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} 9\\ 6\\ 2 \end{array}} \right]\) is: