If \({\rm{E}}\left( {\rm{\theta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\theta }}}&{\sin {\rm{\theta }}}\\ { - \sin {\rm{\theta \;}}}&{\cos {\rm{\theta }}} \end{array}} \right]\) then E(α) E(β) is equal to
E(α + β)
We are given a matrix \({\rm{E}}\left( {\rm{\theta }} \right)\) defined as:
\[{\rm{E}}\left( {\rm{\theta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\theta }}}&{\sin {\rm{\theta }}}\\ { - \sin {\rm{\theta \;}}}&{\cos {\rm{\theta }}} \end{array}} \right]\]We need to find the product of \({\rm{E}}\left( {\rm{\alpha }} \right)\) and \({\rm{E}}\left( {\rm{\beta }} \right)\). Based on the definition of \({\rm{E}}\left( {\rm{\theta }} \right)\), we can write \({\rm{E}}\left( {\rm{\alpha }} \right)\) and \({\rm{E}}\left( {\rm{\beta }} \right)\) by replacing \({\rm{\theta }}\) with \({\rm{\alpha }}\) and \({\rm{\beta }}\) respectively.
\[{\rm{E}}\left( {\rm{\alpha }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\alpha }}}&{\sin {\rm{\alpha }}}\\ { - \sin {\rm{\alpha \;}}}&{\cos {\rm{\alpha }}} \end{array}} \right]\] \[{\rm{E}}\left( {\rm{\beta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\beta }}}&{\sin {\rm{\beta }}}\\ { - \sin {\rm{\beta \;}}}&{\cos {\rm{\beta }}} \end{array}} \right]\]Now, let's multiply \({\rm{E}}\left( {\rm{\alpha }} \right)\) by \({\rm{E}}\left( {\rm{\beta }} \right)\). To multiply two \(2 \times 2\) matrices, we take the dot product of the rows of the first matrix with the columns of the second matrix.
\[{\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\alpha }}}&{\sin {\rm{\alpha }}}\\ { - \sin {\rm{\alpha \;}}}&{\cos {\rm{\alpha }}} \end{array}} \right] \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\beta }}}&{\sin {\rm{\beta }}}\\ { - \sin {\rm{\beta \;}}}&{\cos {\rm{\beta }}} \end{array}} \right]\]Let the resulting matrix be \({\rm{R}} = {\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right) = \left[ {\begin{array}{*{20}{c}} {{{\rm{r}}_{11}}}&{{{\rm{r}}_{12}}}\\ {{{\rm{r}}_{21}}}&{{{\rm{r}}_{22}}} \end{array}} \right]\). We calculate each element:
| Element | Calculation |
|---|---|
| \({\rm{r}}_{11}\) | \((\cos {\rm{\alpha}})(\cos {\rm{\beta}}) + (\sin {\rm{\alpha}})(-\sin {\rm{\beta}}) = \cos {\rm{\alpha}}\cos {\rm{\beta}} - \sin {\rm{\alpha}}\sin {\rm{\beta}}\) |
| \({\rm{r}}_{12}\) | \((\cos {\rm{\alpha}})(\sin {\rm{\beta}}) + (\sin {\rm{\alpha}})(\cos {\rm{\beta}}) = \cos {\rm{\alpha}}\sin {\rm{\beta}} + \sin {\rm{\alpha}}\cos {\rm{\beta}}\) |
| \({\rm{r}}_{21}\) | \((-\sin {\rm{\alpha}})(\cos {\rm{\beta}}) + (\cos {\rm{\alpha}})(-\sin {\rm{\beta}}) = -\sin {\rm{\alpha}}\cos {\rm{\beta}} - \cos {\rm{\alpha}}\sin {\rm{\beta}}\) |
| \({\rm{r}}_{22}\) | \((-\sin {\rm{\alpha}})(\sin {\rm{\beta}}) + (\cos {\rm{\alpha}})(\cos {\rm{\beta}}) = -\sin {\rm{\alpha}}\sin {\rm{\beta}} + \cos {\rm{\alpha}}\cos {\rm{\beta}}\) |
So, the resulting matrix is:
\[{\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\alpha}}\cos {\rm{\beta}} - \sin {\rm{\alpha}}\sin {\rm{\beta}}}&{\cos {\rm{\alpha}}\sin {\rm{\beta}} + \sin {\rm{\alpha}}\cos {\rm{\beta}}}\\ { -(\sin {\rm{\alpha}}\cos {\rm{\beta}} + \cos {\rm{\alpha}}\sin {\rm{\beta}})}&{\cos {\rm{\alpha}}\cos {\rm{\beta}} - \sin {\rm{\alpha}}\sin {\rm{\beta}}} \end{array}} \right]\]We can simplify the elements of this matrix using the angle addition formulas from trigonometry:
Using these identities with \({\rm{A}} = {\rm{\alpha}}\) and \({\rm{B}} = {\rm{\beta}}\), we can rewrite the matrix elements:
Substituting these back into the matrix, we get:
\[{\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos({\rm{\alpha}} + {\rm{\beta}})}&{\sin({\rm{\alpha}} + {\rm{\beta}})}\\ { - \sin({\rm{\alpha}} + {\rm{\beta}})}&{\cos({\rm{\alpha}} + {\rm{\beta}})} \end{array}} \right]\]Let's compare this resulting matrix with the original definition of \({\rm{E}}\left( {\rm{\theta }} \right)\). If we replace \({\rm{\theta }}\) with \({\rm{\alpha}} + {\rm{\beta}}\) in the expression for \({\rm{E}}\left( {\rm{\theta }} \right)\), we get:
\[{\rm{E}}\left( {\rm{\alpha }} + {\rm{\beta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos ({\rm{\alpha }} + {\rm{\beta }})}&{\sin ({\rm{\alpha }} + {\rm{\beta }})}\\ { - \sin ({\rm{\alpha }} + {\rm{\beta }})}&{\cos ({\rm{\alpha }} + {\rm{\beta }})} \end{array}} \right]\]We can see that the result of \({\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right)\) is exactly the same as \({\rm{E}}\left( {\rm{\alpha }} + {\rm{\beta }} \right)\).
Therefore, \({\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right)\) is equal to \({\rm{E}}\left( {\rm{\alpha }} + {\rm{\beta }} \right)\).
| Concept | Description | Relevance to Problem |
|---|---|---|
| Matrix Multiplication | Process of multiplying two matrices to get a new matrix. The element in the i-th row and j-th column of the product is the dot product of the i-th row of the first matrix and the j-th column of the second matrix. | Used to calculate the product \({\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right)\). |
| Angle Addition Formulas | Trigonometric identities relating the cosine and sine of the sum of two angles (\(\cos({\rm{A}} + {\rm{B}})\), \(\sin({\rm{A}} + {\rm{B}})\)) to the sines and cosines of the individual angles. | Used to simplify the elements of the resulting matrix after multiplication. |
| Rotation Matrix | A matrix of the form \({\rm{E}}\left( {\rm{\theta }} \right)\) represents a 2D rotation by angle \({\rm{\theta }}\) counterclockwise around the origin. | Understanding the geometric interpretation helps see why \({\rm{E}}\left( {\rm{\alpha }} \right){\rm{E}}\left( {\rm{\beta }} \right)\) corresponds to a rotation by \({\rm{\alpha}} + {\rm{\beta}}\). |
The matrix \({\rm{E}}\left( {\rm{\theta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\theta }}}&{\sin {\rm{\theta }}}\\ { - \sin {\rm{\theta \;}}}&{\cos {\rm{\theta }}} \end{array}} \right]\) is a standard representation of a 2D rotation matrix. Specifically, it represents a clockwise rotation by angle \({\rm{\theta }}\) about the origin. A counterclockwise rotation matrix is given by \(\left[ {\begin{array}{*{20}{c}} {\cos {\rm{\theta }}}&{ - \sin {\rm{\theta }}}\\ {\sin {\rm{\theta \;}}}&{\cos {\rm{\theta }}} \end{array}} \right]\). The given matrix has \(+\sin {\rm{\theta }}\) in the top right and \(-\sin {\rm{\theta }}\) in the bottom left, which corresponds to a clockwise rotation by \({\rm{\theta }}\). When you apply a rotation by \({\rm{\alpha }}\) followed by a rotation by \({\rm{\beta }}\), the net effect is a rotation by \({\rm{\alpha}} + {\rm{\beta}}\). This geometric property explains why multiplying the matrices \({\rm{E}}\left( {\rm{\alpha }} \right)\) and \({\rm{E}}\left( {\rm{\beta }} \right)\) results in \({\rm{E}}\left( {\rm{\alpha }} + {\rm{\beta }} \right)\). This result is consistent regardless of whether the matrix represents clockwise or counterclockwise rotation, as multiplying rotations corresponds to adding angles.
If \(A=\left[\begin{array}{l}1 \\ 2 \\ 3\end{array}\right]\), then what is the value of det(I + AA'), where I is the 3 × 3 identity matrix?
If \(A=\left[\begin{array}{lll} 2 & 0 & 0 \\ 0 & 3 & 0 \\ 0 & 0 & 4 \end{array}\right]\), then which of the following statements are correct?
1. An will always be singular for any positive integer n.
2. An will always be a diagonal matrix for any positive integer n.
3. An will always be a symmetric matrix for any positive integer n.
Select the correct answer using the code given below:
If \(A=\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right]\), then what is 23A3 - 19A2 - 4A equal to ?
If \(A_k=\left[\begin{array}{cc} k-1 & k \\ k-2 & k+1 \end{array}\right] \), then what is det(A1) + det(A2) + det(A3) + ... + det(A100) equal to ?
Consider the following in respect of the matrix \({\rm{A}} = \left( {\begin{array}{*{20}{c}} { - 1}&1\\ 1&{ - 1} \end{array}} \right):\)
1. A 2= -A
2. A 3= 4A
Which of the above is/are correct?