Consider the following in respect of matrices A and B of same order: 1) A 2– B 2= (A + B) (A – B) 2) (A – I) (I + A) = O ⇔ A 2= I Where I is the identity matrix and O is the null matrix.
2 only
The first statement given is: \( A^2 - B^2 = (A + B) (A - B) \).
Let's expand the right-hand side of the equation, keeping in mind that matrix multiplication is not commutative in general (i.e., \( AB \neq BA \)).
\( (A + B) (A - B) = A(A - B) + B(A - B) \)
\( = A \cdot A - A \cdot B + B \cdot A - B \cdot B \)
\( = A^2 - AB + BA - B^2 \)
For the original statement \( A^2 - B^2 = (A + B) (A - B) \) to be true, we would need \( A^2 - B^2 = A^2 - AB + BA - B^2 \).
This simplifies to \( 0 = -AB + BA \), or \( AB = BA \).
The statement \( A^2 - B^2 = (A + B) (A - B) \) is only true if matrices A and B commute (i.e., \( AB = BA \)). Since the problem statement does not specify that A and B commute, this equation is not generally true for all matrices A and B of the same order.
Therefore, Statement 1 is incorrect in the general case.
The second statement given is: \( (A - I) (I + A) = O \iff A^2 = I \), where \( I \) is the identity matrix and \( O \) is the null matrix.
Let's expand the left-hand side of the equivalence: \( (A - I) (I + A) \).
Using matrix multiplication rules:
\( (A - I) (I + A) = A(I + A) - I(I + A) \)
\( = A \cdot I + A \cdot A - I \cdot I - I \cdot A \)
Recall that for an identity matrix \( I \), \( A \cdot I = A \) and \( I \cdot A = A \), and \( I \cdot I = I \).
\( = A + A^2 - I - A \)
Simplifying the expression:
\( = A^2 + (A - A) - I \)
\( = A^2 + O - I \)
\( = A^2 - I \)
So, the equation \( (A - I) (I + A) = O \) is equivalent to \( A^2 - I = O \).
Adding \( I \) to both sides of the equation \( A^2 - I = O \), we get \( A^2 = I \).
Thus, \( (A - I) (I + A) = O \) is indeed equivalent to \( A^2 = I \).
Therefore, Statement 2 is correct.
Based on our analysis:
Thus, only Statement 2 is correct.
| Property | General Statement | Matrix Equivalent | Condition for Matrices |
|---|---|---|---|
| Difference of Squares | \( a^2 - b^2 = (a-b)(a+b) \) | \( A^2 - B^2 \) | \( (A-B)(A+B) = A^2 + AB - BA - B^2 \) \( (A+B)(A-B) = A^2 - AB + BA - B^2 \) Equality holds iff \( AB = BA \) |
| Identity Expansion | \( (x-1)(x+1) = x^2-1 \) | \( (A-I)(A+I) \) or \( (A-I)(I+A) \) | \( (A-I)(I+A) = A^2 - I \) \( (A-I)(A+I) = A^2 + AI - IA - I^2 = A^2 + A - A - I = A^2 - I \) (Always true because \( AI=IA=A \) and \( I^2=I \)) |
Matrix multiplication is generally not commutative. This means that for two matrices A and B, \( AB \) is usually not equal to \( BA \).
Commutativity (\( AB = BA \)) is a special property that holds only for certain pairs of matrices. For example, any matrix commutes with the identity matrix (\( AI = IA = A \)) and the null matrix (\( AO = OA = O \)). Diagonal matrices of the same order also commute with each other.
Properties from real number algebra, like \( a^2 - b^2 = (a-b)(a+b) \), rely on the commutative property of multiplication (\( ab = ba \)). When extending these properties to matrices, we must carefully check if the non-commutative nature of matrix multiplication affects the result.
In Statement 1, the expansion of \( (A+B)(A-B) \) results in terms involving both \( AB \) and \( BA \). If \( AB \neq BA \), these terms do not cancel out, and the expression does not simplify to \( A^2 - B^2 \).
In Statement 2, the expansion of \( (A-I)(I+A) \) involves terms like \( AI \) and \( IA \). Since \( AI = IA = A \) (identity matrix commutes with any matrix), these terms behave as expected, allowing the simplification to \( A^2 - I \).
If \(A=\left[\begin{array}{l}1 \\ 2 \\ 3\end{array}\right]\), then what is the value of det(I + AA'), where I is the 3 × 3 identity matrix?
If \(A=\left[\begin{array}{lll} 2 & 0 & 0 \\ 0 & 3 & 0 \\ 0 & 0 & 4 \end{array}\right]\), then which of the following statements are correct?
1. An will always be singular for any positive integer n.
2. An will always be a diagonal matrix for any positive integer n.
3. An will always be a symmetric matrix for any positive integer n.
Select the correct answer using the code given below:
If \(A=\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right]\), then what is 23A3 - 19A2 - 4A equal to ?
If \(A_k=\left[\begin{array}{cc} k-1 & k \\ k-2 & k+1 \end{array}\right] \), then what is det(A1) + det(A2) + det(A3) + ... + det(A100) equal to ?
Consider the following in respect of the matrix \({\rm{A}} = \left( {\begin{array}{*{20}{c}} { - 1}&1\\ 1&{ - 1} \end{array}} \right):\)
1. A 2= -A
2. A 3= 4A
Which of the above is/are correct?