Find a matrix X such that 2A + B + X = 0 , where \(A=\begin{bmatrix} -1 & 2 \\\ 3 & 4 \end{bmatrix} \ \text{and} \;\rm B =\ \begin{bmatrix} 3 & -2 \\\ 1 & 5 \end{bmatrix} \ ?\)
The problem asks us to find a matrix X based on the given equation \(2A + B + X = 0\), where matrices \(A=\begin{bmatrix} -1 & 2 \\ 3 & 4 \end{bmatrix}\) and \(B =\begin{bmatrix} 3 & -2 \\ 1 & 5 \end{bmatrix}\) are provided.
To find matrix X, we first rearrange the given equation: \(2A + B + X = 0\) Subtracting \(2A\) and \(B\) from both sides, we get: \(X = - (2A + B)\)
First, we need to perform scalar multiplication on matrix A. We multiply each element of matrix A by 2: $$ 2A = 2 \times \begin{bmatrix} -1 & 2 \\ 3 & 4 \end{bmatrix} $$ $$ 2A = \begin{bmatrix} 2 \times (-1) & 2 \times 2 \\ 2 \times 3 & 2 \times 4 \end{bmatrix} $$ $$ 2A = \begin{bmatrix} -2 & 4 \\ 6 & 8 \end{bmatrix} $$
Next, we add the resulting matrix \(2A\) to matrix B. Matrix addition involves adding corresponding elements: $$ 2A + B = \begin{bmatrix} -2 & 4 \\ 6 & 8 \end{bmatrix} + \begin{bmatrix} 3 & -2 \\ 1 & 5 \end{bmatrix} $$ $$ 2A + B = \begin{bmatrix} (-2 + 3) & (4 + (-2)) \\ (6 + 1) & (8 + 5) \end{bmatrix} $$ $$ 2A + B = \begin{bmatrix} 1 & 2 \\ 7 & 13 \end{bmatrix} $$
Finally, we find matrix X by taking the negative of the result from the previous step \((2A + B)\). This means multiplying each element of \((2A + B)\) by -1: $$ X = - (2A + B) $$ $$ X = - \begin{bmatrix} 1 & 2 \\ 7 & 13 \end{bmatrix} $$ $$ X = \begin{bmatrix} -1 \times 1 & -1 \times 2 \\ -1 \times 7 & -1 \times 13 \end{bmatrix} $$ $$ X = \begin{bmatrix} -1 & -2 \\ -7 & -13 \end{bmatrix} $$
The calculated matrix X is \(\begin{bmatrix} -1 & -2 \\ -7 & -13 \end{bmatrix}\). This matches one of the provided options.
If \(A=\left[\begin{array}{l}1 \\ 2 \\ 3\end{array}\right]\), then what is the value of det(I + AA'), where I is the 3 × 3 identity matrix?
If \(A=\left[\begin{array}{lll} 2 & 0 & 0 \\ 0 & 3 & 0 \\ 0 & 0 & 4 \end{array}\right]\), then which of the following statements are correct?
1. An will always be singular for any positive integer n.
2. An will always be a diagonal matrix for any positive integer n.
3. An will always be a symmetric matrix for any positive integer n.
Select the correct answer using the code given below:
If \(A=\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right]\), then what is 23A3 - 19A2 - 4A equal to ?
If \(A_k=\left[\begin{array}{cc} k-1 & k \\ k-2 & k+1 \end{array}\right] \), then what is det(A1) + det(A2) + det(A3) + ... + det(A100) equal to ?
Consider the following in respect of the matrix \({\rm{A}} = \left( {\begin{array}{*{20}{c}} { - 1}&1\\ 1&{ - 1} \end{array}} \right):\)
1. A 2= -A
2. A 3= 4A
Which of the above is/are correct?