A square matrix A is called orthogonal if_______ where A’ is the transpose of A.
A’ = A -1
A square matrix is a matrix that has the same number of rows and columns. Matrices have special properties and types, one of which is an orthogonal matrix. The question asks for the condition that defines an orthogonal matrix.
A square matrix A is called an orthogonal matrix if its transpose is equal to its inverse. The transpose of a matrix A, denoted by A’ or $A^T$, is obtained by switching the rows and columns of A. The inverse of a matrix A, denoted by $A^{-1}$, is a matrix such that when multiplied by A, it results in the identity matrix (if the inverse exists).
The defining condition for a square matrix A to be orthogonal is:
$$ A’ = A^{-1} $$
This condition is also equivalent to:
$$ AA’ = A’A = I $$
where I is the identity matrix of the same size as A.
Let's look at the provided options and compare them to the definition of an orthogonal matrix:
| Option | Condition | Is it the definition of an Orthogonal Matrix? |
|---|---|---|
| 1 | $A = A^2$ | No, this condition defines an idempotent matrix. |
| 2 | $A’ = A^{-1}$ | Yes, this is the standard definition of an orthogonal matrix. |
| 3 | $A = A^{-1}$ | No, this means A squared is the identity matrix ($A^2 = I$). Such a matrix is called an involutory matrix. |
| 4 | $A = A’$ | No, this condition defines a symmetric matrix. |
Based on the analysis, the condition $A’ = A^{-1}$ is the correct definition of an orthogonal matrix.
Here are some key properties of orthogonal matrices:
Therefore, the correct condition for a square matrix A to be orthogonal is when its transpose A’ is equal to its inverse $A^{-1}$.
| Matrix Type | Defining Condition | Description |
|---|---|---|
| Orthogonal Matrix | $A’ = A^{-1}$ (or $AA’ = I$) | Transpose equals inverse; preserves lengths and angles. |
| Symmetric Matrix | $A = A’$ | Matrix is equal to its transpose. |
| Idempotent Matrix | $A = A^2$ | Multiplying the matrix by itself yields the original matrix. |
| Involutory Matrix | $A = A^{-1}$ (or $A^2 = I$) | Multiplying the matrix by itself yields the identity matrix. |
| Identity Matrix (I) | Square matrix with 1s on the main diagonal and 0s elsewhere. | Multiplying any matrix by the identity matrix (of compatible size) leaves the matrix unchanged. |
| Transpose ($A’$ or $A^T$) | Rows become columns and columns become rows. | Operation performed on a matrix. |
| Inverse ($A^{-1}$) | $AA^{-1} = A^{-1}A = I$ | Matrix that, when multiplied by the original matrix, yields the identity matrix. Not all matrices have an inverse. |
Orthogonal matrices are very important in various fields, including linear algebra, geometry, physics, and computer graphics. Their property of preserving lengths and angles makes them suitable for describing rotations and reflections without distortion. For example, in 3D computer graphics, rotation matrices used to orient objects are typically orthogonal. In quantum mechanics, unitary matrices (which are complex analogues of orthogonal matrices) play a similar role.
Understanding the definition $A’ = A^{-1}$ is fundamental to recognizing and working with orthogonal matrices in mathematical and applied contexts. This condition implies that the columns (and rows) of an orthogonal matrix form a basis of orthonormal vectors, which is a set of vectors that are mutually perpendicular and each have a length of 1.
If \({\rm{E}}\left( {\rm{\theta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\theta }}}&{\sin {\rm{\theta }}}\\ { - \sin {\rm{\theta \;}}}&{\cos {\rm{\theta }}} \end{array}} \right]\) then E(α) E(β) is equal to
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1) (A + B + C)' = A' + B’ + C’
2) (AB)’ = A’B’
3) (ABC)’ = C’B’A’
Where A’ is the transpose of the matrix A.
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If \({\rm{E}}\left( {\rm{\theta }} \right) = \left[ {\begin{array}{*{20}{c}} {\cos {\rm{\theta }}}&{\sin {\rm{\theta }}}\\ { - \sin {\rm{\theta \;}}}&{\cos {\rm{\theta }}} \end{array}} \right]\) then E(α) E(β) is equal to
Consider the following in respect of matrices A, B and C of same order:
1) (A + B + C)' = A' + B’ + C’
2) (AB)’ = A’B’
3) (ABC)’ = C’B’A’
Where A’ is the transpose of the matrix A.
Which of the above are correct?If \({\rm{A}} = \left[ {\begin{array}{*{20}{c}} 1&0&{ - 2}\\ 2&{ - 3}&4 \end{array}} \right]\) , then the matrix X for which 2X + 3A = 0 holds true is
Find a matrix X such that 2A + B + X = 0 , where
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