In a parallelogram, adjacent angles are supplementary (add up to 180 degrees), and opposite angles are equal.
Let the smallest angle of the parallelogram be represented by x.
According to the question, one angle is $48^\circ$ less than twice the smallest angle. This angle can be written as $2x - 48^\circ$.
Since these two angles are adjacent in a parallelogram, their sum must be $180^\circ$.
Therefore, the equation is:
$x + (2x - 48^\circ) = 180^\circ$
So, the smallest angle is $76^\circ$.
The angles in the parallelogram are $x$ and $2x - 48^\circ$. We found $x = 76^\circ$.
Calculate the other angle:
$2x - 48^\circ = 2(76^\circ) - 48^\circ$
$= 152^\circ - 48^\circ$
$= 104^\circ$
The two distinct angles in the parallelogram are $76^\circ$ and $104^\circ$. The largest angle is $104^\circ$.
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