In a parallelogram, consecutive (adjacent) angles add up to $180^\circ$, and opposite angles are equal. Let the smallest angle be represented by '$x$'.
According to the problem, one angle is '$30^\circ$' less than twice the smallest angle. This other angle can be expressed as '$2x - 30^\circ$'.
Since these must be adjacent angles in the parallelogram, their sum is $180^\circ$: $x + (2x - 30^\circ) = 180^\circ$
Now, we solve the equation for '$x$':
So, the smallest angle ($x$) is $70^\circ$. The angles in the parallelogram are $70^\circ$ and $180^\circ - 70^\circ = 110^\circ$.
The two distinct angle measures in the parallelogram are $70^\circ$ (the smallest) and $110^\circ$. We can verify the condition: $2 \times 70^\circ - 30^\circ = 140^\circ - 30^\circ = 110^\circ$. This confirms our angle values.
The largest angle is therefore $110^\circ$.
The measure of the largest angle of the parallelogram is $110^\circ$.
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