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Question

If (b – 6) is one root of the quadratic equation x 2– 6x + b = 0, where b is an integer, then what is the maximum value of b 2?

This question was previously asked in
CDS I 2019 Elementary Mathematics Previous Year Paper (03-Feb-2019)
The correct answer is

81

Finding the Maximum Value of b² in a Quadratic Equation

The problem provides a quadratic equation, \(x^2 – 6x + b = 0\), and states that one of its roots is \((b – 6)\). We are also told that \(b\) is an integer. Our goal is to find the maximum possible value of \(b^2\).

In a quadratic equation \(Ax^2 + Bx + C = 0\), if \(x_0\) is a root, then substituting \(x_0\) into the equation will satisfy it, meaning \(Ax_0^2 + Bx_0 + C = 0\). We can use this property to find the value(s) of \(b\).

Applying the Root Property to the Quadratic Equation

The given equation is \(x^2 - 6x + b = 0\). One root is given as \(x = b - 6\). Let's substitute this root into the equation:

\((b - 6)^2 - 6(b - 6) + b = 0\)

Now, we need to expand and simplify this equation to solve for \(b\).

Solving for the Integer Value(s) of b

Expand the equation:

\((b^2 - 12b + 36) - (6b - 36) + b = 0\)

Remove the parentheses and combine like terms:

\(b^2 - 12b + 36 - 6b + 36 + b = 0\)

\(b^2 + (-12b - 6b + b) + (36 + 36) = 0\)

\(b^2 - 17b + 72 = 0\)

This is a quadratic equation in terms of \(b\). We can solve for \(b\) by factoring, using the quadratic formula, or other methods. Factoring is suitable here as we need two numbers that multiply to 72 and add up to -17. These numbers are -8 and -9.

So, we can factor the equation as:

\((b - 8)(b - 9) = 0\)

This equation holds true if either factor is equal to zero.

  • If \((b - 8) = 0\), then \(b = 8\).
  • If \((b - 9) = 0\), then \(b = 9\).

Since the problem states that \(b\) is an integer, both \(b=8\) and \(b=9\) are valid possible values for \(b\).

Calculating b² for Possible Values of b

We need to find the maximum value of \(b^2\). Let's calculate \(b^2\) for each valid value of \(b\):

  • If \(b = 8\), then \(b^2 = 8^2 = 64\).
  • If \(b = 9\), then \(b^2 = 9^2 = 81\).

Comparing the two possible values for \(b^2\), which are 64 and 81, the maximum value is 81.

Conclusion on Maximum b² Value

Based on our analysis of the quadratic equation and its given root, the possible integer values for \(b\) are 8 and 9. Calculating \(b^2\) for these values gives us 64 and 81, respectively. The maximum among these is 81.

Revision Table: Key Concepts

Concept Description Application in Problem
Root of an Equation A value of the variable that satisfies the equation when substituted. Used to substitute \((b-6)\) for \(x\) in the quadratic equation.
Quadratic Equation An equation of the form \(Ax^2 + Bx + C = 0\), where \(A \ne 0\). The given equation \(x^2 - 6x + b = 0\) is a quadratic equation. The equation derived for \(b\), \(b^2 - 17b + 72 = 0\), is also a quadratic equation.
Factoring Quadratics Expressing a quadratic polynomial as a product of linear factors. Used to solve \(b^2 - 17b + 72 = 0\) for \(b\).
Integer A whole number (positive, negative, or zero). The problem specifies that \(b\) must be an integer, validating our solutions \(b=8\) and \(b=9\).

Additional Information: Quadratic Equation Properties

For a general quadratic equation \(Ax^2 + Bx + C = 0\) with roots \(\alpha\) and \(\beta\), there are some useful properties (Vieta's formulas):

  • Sum of roots: \(\alpha + \beta = -\frac{B}{A}\)
  • Product of roots: \(\alpha \beta = \frac{C}{A}\)

In our given equation \(x^2 - 6x + b = 0\), \(A=1\), \(B=-6\), and \(C=b\). Let the other root be \(\alpha\). The roots are \((b-6)\) and \(\alpha\).

Using the sum of roots property:

\((b-6) + \alpha = -\frac{-6}{1} = 6\)

\(\alpha = 6 - (b-6) = 6 - b + 6 = 12 - b\)

So, the two roots are \((b-6)\) and \((12-b)\).

Using the product of roots property:

\((b-6) \times (12-b) = \frac{b}{1} = b\)

Expand the left side:

\(12b - b^2 - 72 + 6b = b\)

\(-b^2 + 18b - 72 = b\)

Move all terms to one side to form a quadratic equation in \(b\):

\(0 = b^2 - 18b + 72 + b\)

\(b^2 - 17b + 72 = 0\)

This is the exact same quadratic equation for \(b\) that we obtained by substituting the root directly. Solving this equation again gives \(b=8\) or \(b=9\), leading to the same maximum value of \(b^2\) which is 81. This demonstrates that both methods yield the same result and reinforce the properties of quadratic equations and their roots.

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Similar Questions

  1. For what values of k, the roots of 9x 2 + 8kx + 16 = 0 are real and equal?

  2. Consider a question and two statements:

    Question :

    Does the equation ax 2+ bx + c = 0 have real roots of opposite sign?

    Statement – I : The discriminant D > 0

    Statement – II : c / a > 0

    Which one of the following is correct in respect of the question and the statements?

  3. If the sum as well as the product of the roots of the equation px 2- 6x + q = 0 is 6, then what is (p + q) equal to?

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  6. If \(\frac{x}{a} + \frac{y}{b} = a + b\)  and  \(\frac{x}{a^2} + \frac{y}{b^2} = 2\) , then what is  \(\frac{x}{a^2} - \frac{y}{b^2}\)  equal to?

  7. Two numbers p and q are such that the quadratic equation px 2+ 3x + 2q = 0 has – 6 as the sum and the product of the roots. What is the value of (p – q)?

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Important Questions from Quadratic Equation

  1. For what values of k, the roots of 9x 2 + 8kx + 16 = 0 are real and equal?

  2. If \(\rm \left( \frac{x}{x+1} \right)^2 -5 \left( \frac{x}{x+1} \right) +6=0 \) , then the value of  \(\rm \left( 1+\frac{1}{x} \right) \)  is equal to :
  3. If the roots of the equation (q – r)x 2+ (r – p)x + (p – q) = 0 are equal, then which of the following is true?

  4. Number of real roots of the quadratic equation 3x 2+ 4x + 25 = 0 is

  5. The value of m for which one of the root of x 2 - 3x + 2m = 0 is double of the root of x 2 - x + m = 0 is:

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