If \(\sin A = x\), then what is \(\cos^2 A\) in terms of x?
\(1 - x^2\)
Use the fundamental Pythagorean identity:
\(\sin^2 A + \cos^2 A = 1\)
Solve for \(\cos^2 A\):
\(\cos^2 A = 1 - \sin^2 A = 1 - x^2\)
Hence \(\cos^2 A = 1 - x^2\) — option (1).
If $\sin A = \frac{2}{3}$, find the value of $(3\sin A - 4\cos A)^2 + (4\sin A + 3\cos A)^2$.
The value of 4 sin 230° + 3 cot 260° - 2 tan 245° is:
The value of 1 - sin 35° cos 55° is equal to:
If sin 3 θ = cos ( θ – 6°), then θ is:
If θ = 45°, then what will be the value of \(\frac{{\\sin \,\theta \, + \,\cos \,\theta }}{{\sin \,\theta \, - \,\cos \,\theta }}\) ?
If sin A = \(\frac{1}{2}\) and cos B = \(\frac{1}{2}\) then find A + B.