If a two-digit number has a digit sum of 9 and adding 27 reverses its digits, determine the unit digit of the number.
6
Let the tens digit be \(t\) and the unit digit be \(u\), so the number is \(10t + u\).
Given the digit sum: \(t + u = 9\).
Reversing the digits gives \(10u + t\). Adding 27 to the original number produces the reversed number: \((10t + u) + 27 = 10u + t\).
Simplify: \(27 = 9u - 9t = 9(u - t)\), so \(u - t = 3\).
Solve the two equations \(t + u = 9\) and \(u - t = 3\): adding them gives \(2u = 12\), so \(u = 6\) and \(t = 3\).
Check: the number is 36, its reverse is 63, and \(36 + 27 = 63\). Correct.
Hence, the unit digit of the number is 6.
In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.
I. x2 – 26x + 165 = 0
II. y2 – 38y + 357 = 0
Factorize the following:
(x 2- 6xy + 9y 2) - 25
If P and Q are the points on the line Joining A(-2, 5) and B(3, 1) such that
AP = PQ = QB, then the mid point of PQ is
If a number and its reciprocal added it becomes 6, then what will be sum of its square and square of its reciprocal?
If 3x + 2y = 15, and xy = 6. Find the value of (3x3/2) + (4y3/9).