If 24 joules of work is done in moving a charge of 2 coulombs across two points, then what will be the correct voltage across these two points?
12 V
The relationship between work done (W), charge (Q), and voltage (V) is given by the equation:
\(W = VQ\)
Where:
- W is the work done in Joules (J)
- V is the voltage in Volts (V)
- Q is the charge in Coulombs (C)
We are given:
- W = 24 J
- Q = 2 C
We need to find V. Rearranging the equation, we get:
\(V = \frac{W}{Q}\)
Substituting the given values:
\(V = \frac{24 J}{2 C} = 12 V\)
Therefore, the voltage across the two points is 12 V.
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