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Question

If an electric load draws a current of 2 A for 1 second, then calculate the number of electrons (with charge 1.6 × 10⁻¹⁹ C) passing through the load.

This question was previously asked in
RRB NTPC 2024 Undergraduate CBT 1 Question Paper (29-Aug-2025) (Shift 1)
The correct answer is

1.25 × 10¹⁹

Here's how to calculate the number of electrons passing through the load:

1. Find the total charge:

The formula for charge (Q) is given by:

\(Q = I \times t\)

where:

  • \(I\) is the current in Amperes (A)
  • \(t\) is the time in seconds (s)

Given \(I = 2 A\) and \(t = 1 s\), the total charge is:

\(Q = 2 A \times 1 s = 2 C\)

2. Calculate the number of electrons:

We know that the charge of a single electron (e) is \(1.6 \times 10^{-19} C\). To find the number of electrons (n), we can use the following formula:

\(n = \frac{Q}{e}\)

Substituting the values, we get:

\(n = \frac{2 C}{1.6 \times 10^{-19} C} = \frac{2}{1.6} \times 10^{19} = 1.25 \times 10^{19}\)

Therefore, the number of electrons passing through the load is \(1.25 \times 10^{19}\).

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