An electric lamp with a resistance of 35 ohms and a conductor with a resistance of 6 ohms are connected to an 8 V battery in series. Calculate the current flowing through the circuit.
0.2 A
To find the current flowing through the circuit, we use Ohm's Law, which states:
I = V/R
where I is the current, V is the voltage, and R is the total resistance in the circuit.
The total resistance R for components in series is:
R = R1 + R2
Here, R1 = 35 Ω (resistance of the lamp) and R2 = 6 Ω (resistance of the conductor). So,
R = 35 Ω + 6 Ω = 41 Ω
Given the voltage of the battery is V = 8 V, we can calculate the current I:
I = V/R = 8 V / 41 Ω ≈ 0.195 A
Rounding to one decimal place, the current flowing through the circuit is approximately 0.2 A.
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